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Blababa [14]
2 years ago
8

Central school is hosting a “central has talent” show. They will award various prizes for the best 3 acts in the show. First pla

ce wins the most money, and each subsequent place after 1st wins $50 less than the previous place. Let x equal the amount of money first place wins. Which of the following expressions represents the total amount of prize money? Select all that apply
Mathematics
1 answer:
Serjik [45]2 years ago
8 0
Well you didn't post the expressions but let X be the amount of money for first place. This means X-50 would be the amount of second place because <span>each subsequent place after 1st wins $50 less than the previous place. Thirds, would be X-50-50 or X-100

Thus the total amount of money would be all of the values combined which is X+X-50+X-100=3X-150
</span>
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Question show in picture!
Wewaii [24]

Answer: H is the correct answer

Step-by-step explanation:

First, Kendra deposited $78 into her savings. Then, she added $50 more which is 128. She withdraw $27 and was left with $101

5 0
1 year ago
In triangle RST, U is the midpoint of RS, V is the midpoint of ST, and W is the midpoint of TR. Use the triangle diagram to answ
Zolol [24]

(1)

we are given

U is the midpoint of RS

and we have

RU=12

so, we can use formula

RS=2RU

we can plug values

RS=2\times 12

RS=24............Answer

(2)

V is the midpoint of ST

so, we get

SV=VT

now, we can plug values

2x=11

divide both sides by 2

x=5.5.........Answer

(3)

now, we can find y

W is the midpoint of TR

so, we get

RW=WT

we can plug value

15.9=3y

divide both sides by 3

y=5.3

(4)

we can see that

triangles URW and RST are similar

so, their sides ratios must be equal

so, we get

\frac{RW}{RT} =\frac{UW}{ST}

we can plug values

\frac{15.9}{2\times 15.9} =\frac{UW}{2VT}

\frac{15.9}{2\times 15.9} =\frac{UW}{2\times 11}

UW=22\times \frac{15.9}{2\times 15.9}

UW=11...........Answer

(5)

we can see that

triangles SUV and RST are similar

so, their sides ratios must be equal

so, we get

\frac{SU}{SR} =\frac{UV}{RT}

now, we can plug values

\frac{12}{2\times 12} =\frac{UV}{2\times 15.9}

UV=2\times 15.9\times \frac{12}{2\times 12}

UV=15.9.............Answer

4 0
2 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
2 years ago
Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

Given, sum is 10i, difference is -4 and product is -29.

(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

(a-c)+i(b-d)=-4 ⇒ a-c=-4,b-d=0

a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

Hence, all three equations are consistent yielding the complex numbers -2+5i\textrm{ and }2+5i.

8 0
2 years ago
In a second grade class containing 13 girls and 10 boys, 2 students are selected at random to give out the math papers. what is
Natali5045456 [20]
The fact that the first chosen student was a girl is already decided, so there is no need to find the probability of that happening. There are a total of 13+10, or 23 students. A girl was already selected, so that leaves 22 students. The chance that a boy is chosen is 10/22, or 5/11.
4 0
2 years ago
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