Answer: H is the correct answer
Step-by-step explanation:
First, Kendra deposited $78 into her savings. Then, she added $50 more which is 128. She withdraw $27 and was left with $101
(1)
we are given
U is the midpoint of RS
and we have

so, we can use formula

we can plug values

............Answer
(2)
V is the midpoint of ST
so, we get

now, we can plug values

divide both sides by 2
.........Answer
(3)
now, we can find y
W is the midpoint of TR
so, we get

we can plug value

divide both sides by 3

(4)
we can see that
triangles URW and RST are similar
so, their sides ratios must be equal
so, we get

we can plug values



...........Answer
(5)
we can see that
triangles SUV and RST are similar
so, their sides ratios must be equal
so, we get

now, we can plug values


.............Answer
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.
<h2>-2+5i and 2+5i</h2>
Step-by-step explanation:
Let the complex numbers be
.
Given, sum is
, difference is
and product is
.
⇒ 
⇒ 


Hence, all three equations are consistent yielding the complex numbers
.
The fact that the first chosen student was a girl is already decided, so there is no need to find the probability of that happening. There are a total of 13+10, or 23 students. A girl was already selected, so that leaves 22 students. The chance that a boy is chosen is 10/22, or 5/11.