For a better understanding of the solution provided please go through the diagram in the file attached.
Let ABCD be the rectangular yard. The diagonal d=17 meters. AD=8 meters. Therefore, the length of DC can be found by applying the Pythagorean theorem in the right triangle
as:
meters.
Answer:
4.57ft by 1.57 ft
Step-by-step explanation:
We are given that
Emma's square patio has been area=31 sq.ft
One dimension decrease by 1 foot and other dimension decrease by 4 feet.
We have to find the new dimensions of Emma's patio.
Let x be the side of Emma's square patio
We know that
Area of square=

ft
One dimension=
ft
other dimension=
Hence, the new dimension of Emma's patio is given by
4.57ft by 1.57 ft
X = 96
100 137.4
137.4x=(100)(96)
137.4x=9600
137.4x/137.4=9600/137.4
x=70%
Answer
given,
thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
X = U[0.95,1.05] 0.95≤ x ≤ 1.05
the cumulative distribution function of flange
F(x) = P{X≤ x}=
=
b) P(X>1.02)= 1 - P(X≤1.02)
= 
= 0.3
c) The thickness greater than 0.96 exceeded by 90% of the flanges.
d) mean = 
= 1
variance = 
= 0.000833
Answer:
The largest possible area of the deck is 87.11 m² with dimensions;
Width = 9.33 m
Breadth = 9.33 m
Step-by-step explanation:
The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square
Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area
The length of the given railing = 28 m
The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each
The area of a square of side s = s²
The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;
Width = 28/3 m = 9.33 m
Breadth = 28/3 m = 9.33 m.