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2 years ago

Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.

Mathematics

2 answers:

vodka [1.7K]2 years ago

5 0

Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation $(\sqrt[3]{128} )^{x}\\$

According to one of the law of indices,

$(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}$

Applying this law to the question;

$(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )$

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

Rzqust [24]2 years ago

4 0

Answer:

Options B, C, and D on edgenui.ty

Step-by-step explanation:

See the work down above ^^^

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Answer:

Step-by-step explanation:

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2 years ago

PLEASE HELP!! Which steps can be used to solve 6/7x+1/2=7/8 for x? Check all that apply. A. Divide both sides of the equation by

Anon25 [30]

Answer:

B. first step

6/7x=7/8-1/2

c. second step

6/7x=7/8-4/8=3/8

d. and e are the same

x=3/8x7/6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi

vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

8 0

2 years ago

The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}

CaHeK987 [17]

Answer:

The answer is "domain and range are different".

Step-by-step explanation:

Given:

$f(x) = \sqrt{\frac{x+1}{x-1}}\\\\g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\$

Solve f(x) to find domain and range:

for element x: R:

⇒ $x \leq -1 \ \ \ and \ \ \ x > 1$ range:

$for \ \ f(x) \times element : 0 \leq f(x)< 1 \ \ \ or \ \ f(x)>1$

$g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\$

Solve for domain:

⇒ $\ when \ x \ element \ R: \ \ \ x>1$

Solve for range:

⇒ $g(x) \times element$ R : $g(x)>1$

So, the value of the method f(x) and g(x) (range and domain) were different.

5 0

2 years ago

Hospital sends an invoice to a patient. The patient schedules a payment plan in which she makes an initial payment of $1,451 the

Korvikt [17]

First month she payed 1451 dollars

Second month she payed 1/3 of that, which is:
1451/3 = 483.66

Third month she payed 1/3 of 483.66 because as text says, every next month she pays 1/3 of previous month payed amount.

483.66/3 = 161.22

Forth month she payed

161.22/3 = 53.74

In total she payed:

$2149.62 - B.

hope this helps :)

3 0

2 years ago

Read 2 more answers