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Tema [17]
2 years ago
5

Three drivers competed in the same fifteen drag races. The mean and standard deviation for the race times of each of the drivers

are given.
- Driver A had a mean race time of 4.01 seconds and a standard deviation of 0.05 seconds.

- Driver B had a mean race time of 3.96 seconds and a standard deviation of 0.12 seconds.

- Driver C had a mean race time of 3.99 seconds and a standard deviation of 0.19 seconds.


Which driver do you predict will win the next drag race? Support your prediction using the mean and standard deviation.
Mathematics
1 answer:
Monica [59]2 years ago
8 0

Answer:

Driver B

Step-by-step explanation:

From the given options, Driver B will win the next race because the previous result shows that Driver B has the fastest race time due to the fact that it recorded the lowest mean race time.

Similarly, the standard deviation of 0.12 seconds illustrates that the driver keep-up with the bearest minimum time frame all through the entire race time.

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Answer: “Time is like a river.’’ Time is endless And keeps moving “Get busy, time is money!’’ Time is very valuable

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The answer should be 2,800

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Which products result in a perfect square trinomial? Select three options.
Kazeer [188]

Answer:

Second option: (xy+x)(xy+x)

Third option: (2x-3)(-3+2x)

Fifth option: (4y^2+25)(25+4y^2)

Step-by-step explanation:

By definition, a perfect square trinomial can be obtained by squaring binomials.

Then:

(a+b)^2=(a+b)(a+b)=a^2+2ab+b^2\\\\(a-b)^2=(a-b)(a-b)=a^2-2ab+b^2

Knowing this, to obtain a perfect square trinomial, the binomials that you multiply must be equals.

Therefore, the products result in a perfect square trinomial are:

(xy+x)(xy+x)=(xy+x)^2=(xy)^2+2(xy)(x)+x^2=x^2y^2+2x^2y+x^2

(2x-3)(-3+2x)=(2x-3)^2=(2x)^2-2(2x)(3)+3^2=4x^2-12x+9

(4y^2+25)(25+4y^2)=(4y^2+25)^2=(4y^2)^2+2(4y^2)(25)+25^2=16y^4+200y^2+625

8 0
2 years ago
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Two airplanes are flying to the same airport. Their positions are shown in the graph. Write a system of linear equations that re
Liono4ka [1.6K]
To write the system we need the slope of each line and at least one point on the line. The two lines to consider will be the lines connecting the location of each plane to the airport they are flying to. It is also worth noting that the coordinates of the airport represent the point of intersection of the two lines and thus the solution to the system.

1. slope of the line connecting airplane one and the airport: m = 2 you can see this clearly if you graph the two points. From airplane 1 location we rise 8 units and move to the right 4 units to get to the airport. Slope is defined as rise over run: so 8 divided by 4 = 2(the slope) Now substitute the slope and the point (2,4) into point-slope form of a line:

y - 4 = 2(x -4) the standard form of this equation is 2x - y = 0

2. slope of the line connecting airplane 2 and the airport: m = -\frac{1}{3} To find this slope, simply observe the vertical change of down 3 and a horizontal shift of right 9 from the airport to airplane 2. Now substitute this slope and and the point (15,9) into point-slope form of a line:

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Let's write the system:
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Multiply the first equation by 3 to get the new system
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In other words, we have proven that the location of the airport is in fact the solution to our system.




PS: You just have to do a little algebra to get from point-slope form of the two equations to standard form. I did not show this process, but if you need it just let me know... thanks
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Answer:

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Step-by-step explanation:

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