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Nutka1998 [239]
2 years ago
15

The gravitational force between Pluto and Charon is 3.61 × 1018 N. Pluto has a mass of 1.3 × 1022 kg, which is only slightly gre

ater than Charon’s mass of 1.6 × 1021 kg.
How far apart are Pluto and Charon?

a.2.0 × 107 m
b.2.4 × 1012 m
c.3.8 × 1014 m
d.5.8 × 1024 m
Mathematics
1 answer:
Alinara [238K]2 years ago
8 0
Gravitational force:
F = G * m1 * m2 / r²
And gravitational constant: G = 6.67 * 10^(-11) m³/kgs²
Therefore:
r = sqrt ( G * m1 * m2 / F ) =
= sqrt ( 6.67 * 10^(-11) m³/kgs² * 1.3 * 10^(22) kg * 1.6 * 10^(21) / 3.61 * 10^(18) N ) =
= sqrt ( 3.84 * 10^(14) ) = 1.96 * 10^(7) m ≈ 2 * 10^(7) m
Answer:
A ) 2.0 * 10^(7) m 
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Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

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Let f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})

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y=\frac{1728}{x^2} ----1

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0

2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2}  \\y^2=\frac{1728}{x}

Using 1

(\frac{1728}{x^2} )^2=\frac{1728}{x}

x=0 and x^3=1728

Side can never be 0

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z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0
2 years ago
The number of gallons of gas that were in the tank minus 9 leaves 3 gallons
erastovalidia [21]
<h3>Hey!</h3>

<em><u>To solve the missing number of the original amount of gallons that were in the tank is simply by adding the two numbers we have: </u></em>

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So your answer to your question is 12 gallons!

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