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Ivahew [28]
2 years ago
7

Nicolas is setting up water stations for a 10-mile run. He already has the first one set up 8 miles from the starting line. He n

eeds to set up two more that are 1.5 miles on either side of the first water station. Where will he put the two additional water stations?
A number line divided into increments of 1 and labeled 0 through 10. The number 8 is labeled with Nicolas.

The absolute value equation that models this situation is |x –
|=

.

The two additional water stations will be
and

miles from the starting line.

Mathematics
2 answers:
storchak [24]2 years ago
7 0

Answer:

120

Step-by-step explanation:

IceJOKER [234]2 years ago
4 0

Answer:

Step-by-step explanation:

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If the population of a certain city increased 25% in two years, the new population was what percent of the old?
cupoosta [38]
It was 50% bigger than the old city
8 0
2 years ago
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A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so
otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

\hat{p}=\dfrac{25}{123}\approx0.203252

Critical value for 95% confidence interval : z_{\alpha/2}=1.96

Confidence interval for population :

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}

0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0
2 years ago
△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).
dmitriy555 [2]

△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).

The distance between the x-coordinates of R and T is 3 .

The distance between the y-coordinates of R and T is 6.

R' is 1 unit left,2 units up from T, so the coordinates of R' are (2,0)

6 0
2 years ago
Read 2 more answers
A new curing process developed for a certain type of cement results in a mean compressive strength of 5000 kilograms per square
Sedbober [7]

Answer:

\alpha =0.0668

Step-by-step explanation:

Data given and notation  

The info given by the problem is:

n=25 the random sample taken

\mu =5000 represent the population mean

\sigma =100 represent the population standard deviation

The critical region on this case is \bar X so then if the value of \bar X \geq 4970 we fail to reject the null hypothesis. In other case we reject the null hypothesis

Null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the true mean is 5000, the system of hypothesis would be:  

Null hypothesis:\mu = 5000  

Alternative hypothesis:\mu \neq 5000  

Let's define the random variable X ="The compressive strength".

We know from the Central Limit Theorem that the distribution for the sample mean is given by:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

Find the probability of committing a type I error when H0 is true.

The definition for type of error I is reject the null hypothesis when actually is true, and is defined as \alpha the significance level.

So we can define \alpha like this:

\alpha= P(Error I)= P(\bar X

And in order to find this probability we can use the Z score given by this formula:

Z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And the value for the probability of error I is givn by:

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4 0
2 years ago
The value of good wine increases with age. Thus, if you are a wine dealer, you have the problem of deciding whether to sell your
Katyanochek1 [597]

Answer: 64 years

Step-by-step explanation:

Let assume the dealer sold the bottle now for $P, then invested that money at 5% interest. The return would be:

R1 = P(1.05)^t,

This means that after t years, the dealer would have the total amount of:

$P×1.05^t.

If the dealer prefer to wait for t years from now to sell the bottle of wine, then he will get the return of:

R2 = $P(1 + 20).

The value of t which will make both returns equal, will be;

R1 = R2.

P×1.05^t = P(1+20)

P will cancel out

1.05^t = 21

Log both sides

Log1.05^t = Log21

tLog1.05 = Log21

t = Log21/Log1.05

t = 64 years

The best time to sell the wine is therefore 64years from now.

7 0
2 years ago
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