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2 years ago

The graph shows the distance in miles of a runner over x hours. What is the average rate of speed over the interval [9, 11]?

Mathematics

2 answers:

JulsSmile [24]2 years ago

8 0

For this case what you should see is that for the interval [9, 11] the behavior of the function is almost linear.
Therefore, we can find the average rate of change as follows:
m = (y2-y1) / (x2-x1)
m = (11-6) / (11-9)
m = (5) / (2)
m = 5/2
Answer:
the average rate of speed over the interval [9, 11] is:
D. 5 / 2

lora16 [44]2 years ago

3 0

Answer:

Hence, option D is correct.

(i.e. Average speed is 5/2 miles/hour)

Step-by-step explanation:

We are asked to find the average rate of speed over the interval [9, 11].

We know that average speed is given as the ratio of total distance over total time.

the distance when time=9 hours is 6 miles.

and the distance when time=11 hours is 11 miles.

Hence, average speed is given as:

$Average speed=\dfrac{Total distance}{Total time}\\\\Average speed=\dfrac{11-6}{11-9}\\\\Average speed=\dfrac{5}{2}$

Hence average speed is 5/2 miles/hour.

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Raya buys a van for £8500 plus VAT at 20%

asambeis [7]

They buy the van for £8,500 + VAT 20%:

Total paid for the van = £8,500 x 1.20 = £10,200

They make 12 payments of £531.25 for a total of:

12 x £531.25 = £6,375

To find the amount of deposit, subtract the total payments from total cost:

£10,200 - £6,375 = £3,825

The ratio of deposit to the payments is: 3825 : 6375

Reduce the answer by dividing both numbers by 75:

3825/75 = 51

6375 / 75 = 85

The ratio becomes: 51/85

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2 years ago

PQ= 2x +1 and QR= 5x - 44; find PQ

Lena [83]

2x+1=5x-44 that would be your equation

next start to simplify

subtract 1 from both sides so you are left with 2x=5x-45

then subtract 5x from both sides and you have -3x=-45

then finally divide -3 from -45 to get x=15

6 0

2 years ago

Read 2 more answers

We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys

marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation

$\bar X=19.2$ represent the battery life sample mean

$\sigma=2.5$ represent the population standard deviation

$n=25$ sample size

$\mu_o =18$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:

Null hypothesis: $\mu = 18$

Alternative hypothesis: $\mu \neq 18$

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis: $\mu \leq 18$

Alternative hypothesis: $\mu > 18$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4$

4) P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=25-1=24$

Since is a two tailed test for parts I and II, the p value would be:

$p_v =2*P(t_{(24)}>2.4)=0.0245$

And for part III since we have a one right tailed test the p value is:

$p_v =P(t_{(24)}>2.4)=0.0122$

5) Conclusion

I. This finding is significant for a two-tailed test at .05.

Since the $p_v$ . We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0

2 years ago

12700 = 23400 x (1-11.5/100)n

xxTIMURxx [149]

Answer:

Step-by-step explanation:

889

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2 years ago

An up-and-coming artist has 85 followers on Twitter and this number doubles every week. In what week will the artist first reach

Alik [6]

Answer:

5.8 , which approximately is 6 weeks.

Step-by-step explanation:

the first method is the short one since u just have to double the 85 then divide to 1000.

1000 ÷ ( 85 × 2)

1000 ÷ 170 = 5.882,,,,,. round off to whole number to get 6.

the second method is the addition method.

we start by 85 then keep doubling 85 for every week........inshort.......we add 170 to each weeks number to get the number of followers for the following week.

85 ⇒ 170 ⇒ 340 ⇒ 510 ⇒ 680 ⇒ 850 ⇒ 1020.

1st 2nd 3rd 4th 5th 6th week.

u notice that we add (85×2), 170, to get the following week's number of followers..

in 5 weeks..... the number of followers is yet to get to 1000.

when u divide, u get 5.8.....,and it is not logic to say 5.8823....weeks

since she reaches 1000 followers in the 6th week.......though there is an addition,,,, it is the most appropriate answer.

3 0

2 years ago