All u need to do is subtract the bigger number from the smaller one
Use the letters q and d to represent # of quarters and # of dollars.
q + d = 22 coins.
$0.25q + $1.00d = $10.75 Mult. this by 100 to eliminate fractions:
25q + 100d = 1075
Subst. q = 22 - d into the 2nd equation:
25 (22 - d) + 100 d = 1075
550 - 25d + 100d = 1075
550 + 75d = 1075
75 d = 525
d = 7
q + d = 22, so if d = 7, then q = 22-7, or q=15.
There are 15 quarters and 7 dimes.
Okay add 78 and 66. Then add 96 and 108. It should be 144 by 204. I know math is hard, but when you work at it you can do amazing things! I hope that helps you.
We know that the angles of a triangle sum to 180°. For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180
Combining like terms,
16x+20=180
Subtracting 20 from both sides:
16x=160
Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.
For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180
Combining like terms,
20x-20=180
Adding 20 to both sides:
20x=200
Dividing both sides by 20:
x=10
This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.
Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
(9x+10)² or (9x+10)(9x+10)