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diamong [38]
2 years ago
15

A local convenience store in a large city closes each day at 10 P.M. The owner of the store is investigating whether mean sales

will increase by at least $10 per day if the store remains open until 11 P.M. The owner asked the 41 members of a local civic group to estimate the amount of money they might spend during the extra hour. The sample mean was $11.50. The owner will conduct a one-sample tt-test for a population mean.
Have the conditions for inference been met?

A. Yes, all conditions have been met.
B. No, the sample was not chosen using a random method.
C. No, the sample size is greater than 10 percent of the population.
D. No, the sample size is not large enough to assume normality of the sampling distribution.
E. No, the distribution of the sample is not normal.
Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
7 0

Answer:

the answer is B

Step-by-step explanation:

cuz i have already take the test

You might be interested in
The radius of the water well is 9 inches. Find the area of the water well
leva [86]

Answer:

A=254.34

Step-by-step explanation:

1. A=πr²

2. A=π(9)²

3. A=π(81)

4. A=3.14(81)

5. A=254.34

8 0
2 years ago
Read 2 more answers
The value of a car is 18,500. It loses 10.3% of its value every year. Find the approximate monthly decrease in value. Round your
valentina_108 [34]

Answer:

$158.8

Step-by-step explanation:

There are 12 months in 1 year.

If in 1 year, it looses value of 10.3%, so in a month it will loose value of:

10.3%/12 = 0.8583% per month

So, to find the decreased value (in dollars) per month, we got to find 0.8583% of 18,500 dollars.

First, we need to convert percentage to decimal by dividing by 100. Then we multiply that to 18,500 to get our answer. So:

0.8583% = 0.8583/100 = 0.008583

Now,

0.008583 * $18,500 = $158.7855

Rounded to nearest tenth (1 decimal pae) = $158.8

6 0
2 years ago
A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela
nirvana33 [79]

Answer:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.  

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares procedure.  

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal  

The significance level assumed on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.  

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The p value on this case would be given by:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0
2 years ago
HELP ME
Vladimir79 [104]
Alrighty, so, if I remember correctly: For the first question you have 20 possible outcomes, 4 of which are multiples of 5. (5,10,15,20). This gives you 4/20, I multiplied both the numerator and denominator by 200 which then gave me 800/4000. Next I divided which gave me 0.2.
6 0
2 years ago
Marco left his house and went to the sporting goods store to buy a basketball. He then went to jays house. Together the boys hea
mihalych1998 [28]

The map tells you 1 inch = 0.5 miles.

Multiply each dimension on the map by 0.5 to get the miles, then add them together:

House to Sports store = 2 x 0.5 = 1 mile.

Sports store to Jay's house = 3.75 x 0.5 = 1.875 miles.

Jay's house to park = 1.5 + 0.5 = 2 inches x 0.5 = 1 mile.

Total distance = 1 + 1.875 + 1 = 3.875 miles.

4 0
1 year ago
Read 2 more answers
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