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Svetradugi [14.3K]
2 years ago
7

8x + 6y = 10

Mathematics
2 answers:
juin [17]2 years ago
6 0
It could be D or C
The system has two solutions
x = .8 y = .6

OR if you think about it , (x=.8 y=.6) could be considered THE solution.
I would go with choice C

Nitella [24]2 years ago
5 0
Here, Multiply second equation by 2, 
10x - 6y = 4.4

Now, Add both the equations, 
18x = 14.4
x = 14.4 / 18
x = 0.8

Substitute it in 2nd equation, 
5(0.8) - 3y = 2.2
-3y =2.2 - 4
y = 1.8/3
y = 0.6

Solution of the system of Equation is: (0.8, 0.6)

In short, Your Answer would be Option C

Hope this helps!
You might be interested in
The figure below shows the graph of f ', the derivative of the function f, on the closed interval from x = -2 to x = 6. The grap
wolverine [178]

Answer:

x = -2

Step-by-step explanation:

From x = -2 to x = 5, f' is negative.  That means f is decreasing.

From x = 5 to x = 6, f' is positive.  That means f is increasing.

The negative area (between x = -2 and x = 5) is larger than the positive area area (between x = 5 and x = 6).  That means f decreases more than it increases.

So f is an absolute maximum at x = -2.

6 0
2 years ago
1,250 an 15% sale an 6.5 sales tax
eimsori [14]
Given:
price = 1,250
sales discount = 15%
sales tax = 6.5%

The problem is unclear whether the price is the original price or the discounted price. I am assuming that the price is the original price.

Original price times sales discount rate is the value of sales discount
1,250 x 15% = 187.50

Original price less the value of sales discount is the discounted price.
1,250 - 187.50 = 1,062.50

Discounted price times sales tax rate is the value of the sales tax
1,062.50 x 6.5% = 69.06 

Discounted price plus sales tax is the total cost of the purchase
1,062.50 + 69.06 = 1,131.56
4 0
2 years ago
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the​ plate, including t
vredina [299]

You're looking for the extreme values of x^2+3y^2+13x subject to the constraint x^2+y^2\le1.

The target function has partial derivatives (set equal to 0)

\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2

\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0

so there is only one critical point at \left(-\dfrac{13}2,0\right). But this point does not fall in the region x^2+y^2\le1. There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of x^2+y^2\le1 by

x=\cos u

y=\sin u

with 0\le u. Then t(x,y) can be considered a function of u alone:

t(x,y)=t(\cos u,\sin u)=T(u)

T(u)=\cos^2u+3\sin^2u+13\cos u

T(u)=3+13\cos u-2\cos^2u

T(u) has critical points where T'(u)=0:

T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0

(1)\quad\sin u=0\implies u=0,u=\pi

(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4

but |\cos u|\le1 for all u, so this case yields nothing important.

At these critical points, we have temperatures of

T(0)=14

T(\pi)=-12

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0
1 year ago
Juan invest $3700 in a simple interest account at a rate of 4% for 15 years
OleMash [197]

<em><u>Question:</u></em>

Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?

<em><u>Answer:</u></em>

There will be $ 5920 in account after 15 years

<em><u>Solution:</u></em>

<em><u>The simple interest is given by formula:</u></em>

S.I = \frac{p \times n \times r }{100}

Where,

p is the principal

n is number of years

r is rate of interest

From given,

p = 3700

r = 4 %

t = 15 years

Therefore,

S.I = \frac{3700 \times 4 \times 15 }{100}\\\\S.I = 37 \times 4 \times 15\\\\S.I = 2220

<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>

Total money = principal + simple interest

Total money = 3700 + 2220

Total money = 5920

Thus there will be $ 5920 in account after 15 years

8 0
2 years ago
The table below shows the functions to represent the sale f(t), in thousands, of four companies in t years.
Tcecarenko [31]
Hi there

the companies showed an exponential growth in sale are

Company C with
f(t) = 1.26t

Company D with
f(t) = 1.09t

Because
1+r where r is the rate of growth

the rate of growth of Company c is 1+26%

The rate of growth of company D is
1+9%


So it's option d

Good luck!
4 0
1 year ago
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