A race car driving under the caution flag at 40 feet per second begins to accelerate at a constant rate after the warning flag.
The distance traveled since the warning flag in feet is characterized by 30t2 + 40t, where t is the time in seconds after the car starts accelerating again. How long will the car take to travel 150 feet?
1 answer:
Answer:
t = 1.667 s
Step-by-step explanation
The distance traveled since the warning flag in feet is characterized by
d = 30*t^2 + 40*t
Where t is the time in seconds after the car starts accelerating.
We can easily solve this question by plotting the equation using a graphing calculator or plotting tool.
We need to find the time for which the distance d = 150 ft
150 = 30*t^2 + 40*t , t > =0
We can see that this value in the graph is approximately
t = 1.667 s
We can verify
30*(1.667)^2 + 40*(1.667 ) ≈ 150
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Step-by-step explanation:
The steps are as follows :
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4. Multiply both sides by the reciprocal of 13/8 to isolate variable X
5. Simplify
6. Check answer by using it in the original equation