What is the word form of 34/100

A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte

Natasha2012 [34]

Answer:

D. The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

Step-by-step explanation:

The treatment group using System A reported a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.

The best conclusion that can be made is - The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

As we know, in statistics, nothing happens by chance. So, this option is correct.

8 0

2 years ago

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The mean GPA of student in a course at UCDevis is 3.2 with a standard deviation of 0.3. What percent of student in a course have

Orlov [11]

Answer:

81.86%

Step-by-step explanation:

We are given that the mean GPA of students in a course at UC Davis is 3.2 with a standard deviation of 0.3.

Assuming that the data follows normal distribution.

Let X = GPA of students in a course at UC Davis

So, X ~ Normal()

The z score probability distribution for normal distribution is given by;

Z = ~ N(0,1)

where, = population mean GPA = 3.2

= standard deviation = 0.3

Now, the probability that the students in the course have a GPA between 2.9 and 3.8 is given by = P(2.9 < X < 3.8)

P(2.9 < X < 3.8) = P(X < 3.8) - P(X 2.9)

P(X < 3.8) = P( < ) = P(Z < 2) = 0.97725

P(X 2.9) = P( ) = P(Z -1) = 1 - P(Z < 1)

= 1 - 0.84134 = 0.15866

The above probability is calculated by looking at the value of x = 2 and x = 1 in the z table which has an area of 0.97725 and 0.84134 respectively.

Therefore, P(2.9 < X < 3.8) = 0.97725 - 0.15866 = 0.8186

Hence, 81.86% of students in the course have a GPA between 2.9 and 3.8.

5 0

2 years ago

1) A 1.5 kg apple pie is sitting on the kitchen counter . If it has 13.44 J of gravitational potential energy, how tall is the c

vampirchik [111]

a)

Answer: 0.91 m

Explanation:

We know that,

P.E. = m g h

Where,

P.E = Potential energy

m = Mass of the object

g = acceleration due to gravity (9.8 m/s²)

It is given that, m = 1.5 kg

P.E. = 13.44 J

⇒ 13.44 = 1.5 kg × 9.8 m/s² × h

⇒ h = 0.91 m

Hence, apple sits om 0.91 m tall counter.

b)

Answer: 216 J

Explanation:

P.E. = m g h

Weight, mg = 120 N ( given)

height, h = 1.8 m ( given)

The energy possessed by the suitcase is due to virtue of its position (gravitational potential energy)

P.E. = 120 N × 1.8 m = 216 J

Hence, the energy possessed by the suitcase sitting on the counter is 216 J.

8 0

2 years ago

Select the term that does NOT describe the triangle. Select all that apply

emmainna [20.7K]

Answer:

this isnt an isosceles.

3 0

2 years ago

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According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m

tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

$P(A) = 0.8x + 0.25*0.2x = 0.85x$