Answer:
1/9; 4/9; 1/12; 1/6
Step-by-step explanation:
the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9
the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9
the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12
the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6
-120 ÷ 15 = -8.
Hope this helps.
In this specific problem each term is separated by an addition sign , so you have a total of 3 terms . The correct answer is " C."<span />
Answer: 0.05
Step-by-step explanation:
Let M = Event of getting an A in Marketing class.
S = Event of getting an A in Spanish class,
i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45
Required probability = P(neither M nor S)
= P(M'∩S')
= P(M∪S)' [∵P(A'∩B')=P(A∪B)']
=1- P(M∪S) [∵P(A')=1-P(A)]
= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]
= 1- (0.80+0.60-0.45)
= 1- 0.95
= 0.05
hence, the probability that Helen does not get an A in either class= 0.05
Answer:
6
Step-by-step explanation: 31.50 devided by 5.25 = 6
