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777dan777 [17]
2 years ago
5

Farmer frank owns a piece of grassland. The grass grows at a constant rate and each cow eats at a constant rate. 12 cows can eat

10 acres of grass in 28 days. 21 cows can eat 30 acres of grass in 63 days. How many cows can eat 72 acres of grass in 126 days?
Mathematics
1 answer:
MrRa [10]2 years ago
3 0

Answer: There are 36 cows that can eaten 72 acres of grass in 126 days.

Step-by-step explanation:

Let x be the amount of grass in an acre initially.

Let y be the amount of grass grown in an acre per day.

Since we have given that

12 cows can eat 10 acres of grass in 28 days

12×28  = 10x + 10×28 y

336 = 10x + 280 y----------------------------(1)

Similarly,

21 cows can eat 30 acres of grass in 63 days.

21×63  = 30x + 30×63 y

1323 = 30x +1890 y ---------------------------(2)

So, by graphing method, we get the value of x and y

x=\dfrac{126}{5},\ y=\dfrac{3}{10}

So, we have,  72 acres of grass in 126 days, we need to find the number of cows.

So, it becomes,

c×126 = 72x + 72×126 y

126c=72\times \dfrac{126}{5}+72\times 126\times \dfrac{3}{10}\\\\126x=4536\\\\x=\dfrac{4536}{126}\\\\x=36

Hence, there are 36 cows that can eaten 72 acres of grass in 126 days.

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Answer:

The claim is not fair because:

  • Probability of roliing two 6s = Probability of rolling two 3s = 1/36

Step-by-step explanation:

The <em>probaility</em> of an event is defined as the number of favorable outcomes divided by the number of total possible events.

P (event E) = number of outcomes for event E / number of possible events

1. <u>As </u><u>first step</u><u>, you may draw a table to find the </u><u>sample space</u><u> (set of all possible outcomes)</u>.

<u>Sample space</u>

The results of the rolling two dice are summarized in this table:

                    Second roll    1       2       3       4        5      6

First roll

  1                                       (1,1)  (1,2)    (1,3)   (1,4)   (1,5)  (1,6)

  2                                     (2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

  3                                     (3,1)  (3,2)  <u>(3,3)</u>   (3,4)  (3,5)  (3,6)

  4                                     (4,1)   (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

  5                                     (5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

  6                                     (6,1)  (6,2)  (6,3)  (6,4)  (6,5)  <u>(6,6)</u>

<u></u>

2.<u>Now, in that table, you can observe</u>:

The results (3,3) and (6,6) are highlited.

a) Total number of events: 6 × 6 = 36

b) Nnmber of outcomes for the event rolling two 6s (6,6): 1

c) Number of outcomes for the event rolling two 3s (3,3): 1

3) <u>Next, you can calculate the probabilities:</u>

a) Probability rolling two 6s = 1 / 36

b) Probability of rolling two 3s: 1 / 36

4. <u>Conclusion</u>: the probabilities prove that rolling two 6s is just as likely as rolling two 3s.

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