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2 years ago

Matthew goes hiking every 12 days and swimming every 6 days. He did both

Mathematics

1 answer:

AlexFokin [52]2 years ago

3 0

The next 18 days because your trying to see how many days it is until he does BOTH

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Lori ran the distances shown in the table. write the total distance in miles as a fraction in simplest form

daser333 [38]

0.35+0.2+.25
=0.55+0.2
=0.57
=57/100 miles

8 0

2 years ago

Grandpa ernie is shrinking! Over the past 4 years, his hight decressed by a total of 2.4cm. It decresed by the same amount each

dolphi86 [110]

Answer: 0.6 cm

Step-by-step explanation:

Given : Over the past 4 years, Grandpa Ernie's height decreased by a total of 2.4 cm.

If the height is decreased by the same amount each year.

Then, the change in Grandpa Ernie's height each year will be =

Total decrease in height ÷ 4

= 2.4 cm ÷ 4 = 0.6 cm

Hence, the change in Grandpa Ernie's height each year = 0.6 cm

4 0

2 years ago

Read 2 more answers

Kim is reading a book with 380 pages. She read 20 pages each day until she reached Part 2 of the book. Part 2 of the book is 160

d1i1m1o1n [39]

If you divide 380 by 20, you get 19. To check this, multiply 20 x 19 to see 380. Hope this helps :D

6 0

2 years ago

Read 2 more answers

the sugar is sold at rupees 5.4 per kg at a loss of 10% at what price relative is sold per kg to earn a profit of 20%

ladessa [460]

Answer:

the price sold per kg to earn a profit of 20% is 7.2 kg

Step-by-step explanation:

The computation of the price sold per kg to earn a profit of 20% is shown below:

But before that the normal price per kg is

= 5.4 per kg × 100 ÷ 90

= 6 per kg

Now for 20% profit, the price per kg is

= 6 × (1 + 0.20)

= 6 + 1.2

= 7.2 kg

hence, the price sold per kg to earn a profit of 20% is 7.2 kg

5 0

2 years ago

Upgrading a certain software package requires installation of 68 new files. Files are installed consecutively. The installation

ser-zykov [4K]

Answer:

The probability that the whole package is uppgraded in less then 12 minutes is 0,1271

Step-by-step explanation:

The mean distribution for the length of the installation (in seconds) of the programs will be denoted by X. Using the Central Limit Theorem, we can assume that X is normal (it will be pretty close). The mean of X is 15 and the variance is 15, hence, the standard deviation is √15 = 3.873.

We want to find the probability that the full installation process takes less than 12 minutes = 720 seconds. Then, in average, each program should take less than 720/68 = 10.5882 seconds to install. Hence, we want to find the probability of X being less than 10.5882. For that, we will take W, the standariation of X, given by the following formula

$W = \frac{X-\mu}{\sigma} = \frac{X-15}{3.873}$

We will work with $\phi$ , the cummulative distribution function of the standard Normal variable W. The values of $\phi$ can be found in the attached file.

$P(X < 10.5882) = P(\frac{X-15}{3.873} < \frac{10.5882-15}{3.873}) = P(W < -1,14)$

Since the density function of a standard normal random variable is symmetrical, then $\phi(-1.14) = 1-\phi(1.14) = 1-0.8729 = 0.1271$

Therefore, the probability that the whole package is uppgraded in less then 12 minutes is 0,1271.

Download pdf

7 0

2 years ago