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frozen [14]
2 years ago
11

Matthew goes hiking every 12 days and swimming every 6 days. He did both

Mathematics
1 answer:
AlexFokin [52]2 years ago
3 0
The next 18 days because your trying to see how many days it is until he does BOTH
You might be interested in
Ivan and Jeff buy a package of 8 pens for $4.00. Ivan wants 5 of the pens, and Jeff wants 3. How much should each student pay?
irga5000 [103]
$4 / 8 = 50 cents per pen

.5 * 5 = 2.50
.5 * 3 = 1.50

Ivan pays $2.50 and Jeff pays $1.50
3 0
2 years ago
If week 1=5, week 2=3, week 3=7, week 4=5 what will week 5 be?
olga2289 [7]

Answer: 11

Step-by-step explanation:

The sequence goes +4, +1, +5, +1... so obviously the next number will be +6. So, 5+6=11

The answer is week 5=11

4 0
2 years ago
According to a Pew Research survey, about 27% of American adults are pessimistic about the future of marriage and the family. Th
IgorLugansk [536]

Answer:

P(X≤5)=0.5357

Step-by-step explanation:

Using the binomial model, the probability that x adults from the sample, are pessimistic about the future is calculated as:

P(x)=\frac{n!}{x!(n-x)!} *p^{x}*(1-p)^{n-x}

Where n is the size of the sample and p is the probability that an adult is pessimistic about the future of marriage and family. So, replacing n by 20 and p by 0.27, we get:

P(x)=\frac{20!}{x!(20-x)!}*0.27^{x}*(1-0.27)^{20-x}

Now, 25% of 20 people is equal to 5 people, so the probability that, in a sample of 20 American adults, 25% or fewer of the people are pessimistic about the future of marriage and family is equal to calculated the probability that in the sample of 20 adults, 5 people of fewer are pessimistic about the future of marriage and family.

Then, that probability is calculated as:

P(X≤5)= P(1) + P(2) + P(3) + P(4) + P(5)

Where:

P(0)=\frac{20!}{0!(20-0)!}*0.27^{0}*(1-0.27)^{20-0}=0.0018

P(1)=\frac{20!}{1!(20-1)!}*0.27^{1}*(1-0.27)^{20-1}=0.0137

P(2)=\frac{20!}{2!(20-2)!}*0.27^{2}*(1-0.27)^{20-2}=0.0480\\P(3)=\frac{20!}{3!(20-3)!}*0.27^{3}*(1-0.27)^{20-3}=0.1065\\P(4)=\frac{20!}{4!(20-4)!}*0.27^{4}*(1-0.27)^{20-4}=0.1675\\P(5)=\frac{20!}{5!(20-5)!}*0.27^{5}*(1-0.27)^{20-5}=0.1982

Finally, P(X≤5) is equal to:

P(X≤5) = 0.0018+0.0137 + 0.0480 + 0.1065 + 0.1675 + 0.1982

P(X≤5) = 0.5357

3 0
2 years ago
Each year at a college, there is a tradition of having a hoop rolling competition.
zhuklara [117]

Answer:

12.5kg

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
The frequency distribution of weights (in kg) of 40 persons is given below.
gregori [183]

Answer: (a) 4

(b) 5

(c) 14

(d)

Class interval       Class mark

30 - 35                       \dfrac{35+30}{2}=32.5

35 - 40                       \dfrac{35+40}{2}=37.5

40 - 45                        \dfrac{40+45}{2}=42.5

45 - 50                        \dfrac{45+50}{2}=47.5

50 - 55                        \dfrac{50+55}{2}=52.5

Step-by-step explanation:

The data of 40 persons is given as :

Weights (in kg)    Frequency

30 - 35                  6

35 - 40                   13

40 - 45                   14

45 - 50                   4

50 - 55                  3

(a)

<em>Lower limit is the lowest number in a class interval .</em>

So, is the lower limit of fourth-class interval (45 - 50) is 4.

(b)

<em>Class size = Upper limit - lower limit </em>

So, Class size of first class interval = 35-30=5

Thus , class size of each interval is 5. [ class size remains same]

(c)

Highest frequency in table = 14 which is corresponding to 40 - 45   .

Thus , 40 - 45  is the class interval has the highest frequency.

(d)

<em>Class mark is the mid value of each class interval.</em>

<em>Class interval = </em>\dfrac{(\text{Upper limit+Lower limit})}{2}

Class interval       Class mark

30 - 35                       \dfrac{35+30}{2}=32.5

35 - 40                       \dfrac{35+40}{2}=37.5

40 - 45                        \dfrac{40+45}{2}=42.5

45 - 50                        \dfrac{45+50}{2}=47.5

50 - 55                        \dfrac{50+55}{2}=52.5

8 0
2 years ago
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