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2 years ago

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The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) us

ing a point and the slope. Which point did Harold use? When Harold wrote his equation, the point he used was (7, 3). When Harold wrote his equation, the point he used was (0, 7). When Harold wrote his equation, the point he used was (7, 0). When Harold wrote his equation, the point he used was (3, 7).

2 answers:

xz_007 [3.2K]2 years ago

8 0

For this case we must find the point that Harold used to arrive at the following equation:

$y = 3 (x-7)$

Starting from the fact that the equation of the point-slope form of a line is given by:

$(y-y_ {1}) = m (x-x_ {1})$

If we compare the standard equation with Harold's, we see that the slope of the line is $m = 3.$

In addition, it is observed that $x_ {1} = 7$ and $y_ {1} = 0.$

Then, the correct option is: Harold used the point (7,0)

ANswer:

When Harold wrote his equation, the point was used (7,0).

Kamila [148]2 years ago

8 0

Answer:

c

Step-by-step explanation:

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