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Elanso [62]
2 years ago
7

the garza family drives to a state park. the remaining distance, in miles, to reach the state park is 285−60x , where x represen

ts the number of driving hours. what does each part of the expression represent? drag the answer into the box to match each part of the expression. 285 60x 60 the number of miles left to drive each daythe number of miles driven after 1 hourthe number of miles driven after x hoursthe total distance to the state park
Mathematics
2 answers:
zaharov [31]2 years ago
8 0

Answer:

The Answer is

285 = The total distance to the state park.

60x = The number of miles driven after x hours.

60 = The number of miles driven after 1 hour.


Step-by-step explanation:


alukav5142 [94]2 years ago
5 0
285 - 60x ; where x represents the number of driving hours.

285 ⇒ <span>The total distance to the state park.
60x </span>⇒<span> </span><span>The number of miles driven after x hours.
60 </span>⇒<span> </span><span>The number of miles driven after 1 hour.

y = 285 - 6x
y </span>⇒<span> </span><span>The number of miles left to drive each day.</span>
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2.8571 i think im not sure
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Un equipo de fútbol se conforma de cuatro líneas de jugadores: portero (9%), defensas (37%), medios (27%) y delanteros (27%), do
Tpy6a [65]

Answer:

According to the proble, the total number of goals are 1+11+15+23 = 50: 1 by the goalkeeper, 11 by defense, 15 by midfielders and 23 by strikers.

So, each probability can be found by using standard probabilities

P=\frac{events}{total outcomes}

<h3>(a) Defense</h3>

P=\frac{11}{50} \approx 0.22

Therefore, the defense has a probability of 22% of score that goal.

<h3>(b) Midfielders</h3>

P=\frac{15}{50} \approx 0.30

Therefore, midfielders have a probability of 30% of scoring that goal.

<h3>(c) Strikers.</h3>

P=\frac{23}{50} \approx 0.46

Therefore, strikers have a probability of 46% of scoring that goal.

3 0
2 years ago
estimate the total weight of two boxes that weigh 9.4 lb and 62.6 lb using rounding and compatible numbers. which estimate is cl
Scorpion4ik [409]
<span><span>1.       </span>We have 2 boxes weighs:
=> 9.4 lb and 62.6 lbs.
Now, let’s estimate the total weight of this 2 boxes using rounding and compatible numbers.
For 9.4 lbs , the rounded and compatible number is 9 lbs
And for 62.6 lbs, the rounded and compatible number is 63 lbs
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=> 9 +63
=> 72 = the estimated and rounded answer is 72.
Let’s check if we have close answer
=> 9.4 + 62.6
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5 0
2 years ago
The Acme Candy Company claims that​ 60% of the jawbreakers it produces weigh more than 0.4 ounces. Suppose that 800 jawbreakers
vichka [17]

Answer:

Yes, it would be statistically significant

Step-by-step explanation:

The information given are;

The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%

Number of jawbreakers in the sample, n = 800

The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = \mu _ {\hat p} =p

The formula for the standard deviation of a proportion is \sigma  _{\hat p} =\sqrt{\dfrac{p(1-p)}{n} }

Solving for the standard deviation gives;

\sigma  _{\hat p} =\sqrt{\dfrac{0.6 \cdot (1-0.6)}{800} } = 0.0173

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4  in the sample of 800 = 800*0.6 = 480

For statistical significance the difference from the mean = 2×\sigma _{\hat p} = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7

The z-score of 494 jawbreakers is given as follows;

Z=\dfrac{x-\mu _{\hat p} }{\sigma _{\hat p}  }

Z=\dfrac{494-480 }{0.0173  } = 230.94

Therefore, the z-score more than 2 ×\sigma _{\hat p} which is significant.

8 0
2 years ago
Evaluate the expression. P(9, 3) · P(5, 4)
boyakko [2]

Answer:

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

Step-by-step explanation:

For this problem we want to find the following expressionÑ

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

6 0
2 years ago
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