2.8571 i think im not sure
Answer:
According to the proble, the total number of goals are 1+11+15+23 = 50: 1 by the goalkeeper, 11 by defense, 15 by midfielders and 23 by strikers.
So, each probability can be found by using standard probabilities

<h3>(a) Defense</h3>

Therefore, the defense has a probability of 22% of score that goal.
<h3>(b) Midfielders</h3>

Therefore, midfielders have a probability of 30% of scoring that goal.
<h3>(c) Strikers.</h3>

Therefore, strikers have a probability of 46% of scoring that goal.
<span><span>1. </span>We
have 2 boxes weighs:
=> 9.4 lb and 62.6 lbs.
Now, let’s estimate the total weight of this 2 boxes using rounding and
compatible numbers.
For 9.4 lbs , the rounded and compatible number is 9 lbs
And for 62.6 lbs, the rounded and compatible number is 63 lbs
=> now, let’s try adding both numbers if we get a close answer
=> 9 +63
=> 72 = the estimated and rounded answer is 72.
Let’s check if we have close answer
=> 9.4 + 62.6
=> 72</span>
Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 =
=p
The formula for the standard deviation of a proportion is 
Solving for the standard deviation gives;

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2×
= 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;


Therefore, the z-score more than 2 ×
which is significant.
Answer:

And if we use the permutation formula given by:

And replacing we got:

Step-by-step explanation:
For this problem we want to find the following expressionÑ

And if we use the permutation formula given by:

And replacing we got:
