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ratelena [41]
1 year ago
5

Marcos has been dealt seven different cards. How many different ways can he play his cards if he is required to play one card at

a time?
Mathematics
2 answers:
stepladder [879]1 year ago
6 0
 5,040 ways 

He has 7 choices to pick his first card, 6 choices for his second, and so on. Multiply the number of choices to get the answer.
vfiekz [6]1 year ago
5 0

Answer:

There are 5040 ways he can play his cards if he is required to play one card at a time.

Step-by-step explanation:

Given :Marcos has been dealt seven different cards.

To Find :How many different ways can he play his cards if he is required to play one card at a time?

Solution:

No. of cards = 7

He is required to play one card at a time

So, For first draw he has 7 choices

For second draw he will have 6 choices and so on

On seventh draw all cards will be drawn .

So, No. of ways he can play his cards if he is required to play one card at a time= 7! = 7 \times 6 \times 5 \times 4\times 3 \times 2 \times 1 =5040

Hence There are 5040 ways he can play his cards if he is required to play one card at a time.

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Adita has two options for how to invest $1,000. Plan A: Put the $1,000 in an account that pays $100 per year. Plan B: Put the $1
cluponka [151]

Answer:

Plan A = 1000 dollars to be invested in an account that pays 100 dollars per year. (1000 + 100 = 1100 dollars in a year)

Plab B = 1000 dollars to be invested in an account that pays 5% interests per year  (1000 * .05 = 50 => 1000 + 50 = 1050 dollars per year)

The correct answer is Plan A will be worth more than plan B after two years.

Step-by-step explanation:

Plan A = 1000 dollars to be invested in an account that pays 100 dollars per year. (1000 + 100 = 1100 dollars in a year)

Plab B = 1000 dollars to be invested in an account that pays 5% interests per year  (1000 * .05 = 50 => 1000 + 50 = 1050 dollars per year)

3 0
1 year ago
How many marbles, each with a volume of 36 cubic centimeters, are needed to fill in a cylindrical vase with a radius of 6 centim
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The volume of a cylinder can be found using the formula:

π r² h, 

where r is the radius of the circular base and h is the height of the cylinder.

If we plug in the measurements of the cylinder, we get:

π (6²) (28)

When this is simplified, we get that the volume of the cylinder is:

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Thus, if each marble has a volume of 36π cubic cm, then to find how many marbles will fit into the vase we must divide the vases total volume by the volume of each marble.

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7 0
2 years ago
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After a certain medicine is ingested, its concentration in the bloodstream changes over time.
myrzilka [38]

Answer:

Every hour, the medicine concentration decays by a factor of 4%.

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The relationship between the elapsed time, <em>t</em>, in minutes, since the medicine was ingested, and its concentration in the bloodstream, <em>C</em> (<em>t</em>), is:

C(t)=61\cdot (0.96)^{t}

The decay function is:

y=a(1-r)^{t}

Here,

<em>y</em> = final amount

<em>a </em>= initial amount

<em>r</em> = decay rate

<em>t</em> = time

From the provided expression the decay rate is:

1-r=0.96\\r=1-0.96\\r=0.04

Thus, every hour, the medicine concentration decays by a factor of 4%.

8 0
2 years ago
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calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-
Tatiana [17]

Answer:

1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10

Step-by-step explanation:

We can use the distance formula to calculate the lengths of the line segments.

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

1. A (1,5), B (4,5) (red)

d = \sqrt{(x_{2} - x_{1}^{2}) + (y_{2} - y_{1})^{2}} = \sqrt{(4 - 1)^{2} + (5 - 5)^{2}}\\= \sqrt{3^{2} + 0^{2}} = \sqrt{9 + 0} = \sqrt{9} = \mathbf{3}

2. A (2,-5), B (2,7) (blue)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(2 - 2)^{2} + (7 - (-5))^{2}}\\= \sqrt{0^{2} + 12^{2}} = \sqrt{0 + 144} = \sqrt{144} = \mathbf{12}

3. A (3,1), B (-1,4 ) (green)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-1 - 3)^{2} + (4 - 1)^{2}}\\= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = \mathbf{5}

4. A (-2,-5), B (3,7) (orange)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 - (-2))^{2} + (7 - (-5))^{2}}\\= \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = \mathbf{13}

5. A (5,4), B (-3,-2) (purple)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-3 - 5)^{2} + (-2 - 4)^{2}}\\= \sqrt{(-8)^{2} + (-6)^{2}} = \sqrt{64 + 36} = \sqrt{100} = \mathbf{10}

6. A (1,-8), B (-5,0) (black)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-5 - 1)^{2} + (0 - (-8))^{2}}\\-= \sqrt{(-6)^{2} + (-8)^{2}} = \sqrt{36 + 64} = \sqrt{100} = \mathbf{10}

6 0
1 year ago
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