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liraira [26]
2 years ago
11

Athletes in a particular sport are classified as either offense or defense. The distribution of weights for the athletes classif

ied as offense is approximately normal, centered at 200 pounds, and ranges from 150 pounds to 250 pounds. The distribution of weights for the athletes classified as defense is approximately normal, centered at 300 pounds, and ranges from 250 pounds to 350 pounds. There are 1,000 athletes in each classification. Which of the following is the best description of a histogram of the weights of all 2,000 athletes?
A. Skewed to the right (positively skewed).
B. Skewed to the left (negatively skewed).
C. Approximately uniform and centered at 250 pounds.
D. Approximately normal and centered at 250 pounds.
E. Bimodal.
Mathematics
1 answer:
Evgen [1.6K]2 years ago
6 0

Answer:

E. Bimodal.

Step-by-step explanation:

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Simplify the following expression, if you can see the picture the expression is as follows:
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As the number of pages in a photo book increases, the price of the book also increases. There is an additional shipping charge o
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Answer:

22

Step-by-step explanation:

Solve the inequality  (20 + 0.5x) + 0.15(20 + 0.5x)   ≤ $62.10 for x:

20 + .5x + 3 + 0.75x ≤ 62.10

Combining the x terms, we get:

20 + 3 + 1.25x ≤ 62.10.

Combining the constants on the left:

23 + 1.75x ≤ 62.10

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2 years ago
In college basketball, some teams get most of their points from just one player, and other teams are more balanced in scoring. C
lutik1710 [3]

Answer:

(B) At Maryland, the mean number of points per player per game is greater than the median number of points per player per game.

(D)The mean number of points per player per game is the same at all 3 schools.

Step-by-step explanation:

<u>Baylor University</u>

6 players who each score 12 points per game

6 players who each score 0 points per game.

The Scores are: 0,0,0,0,0,0,12,12,12,12,12,12

Mean=\frac{0+0+0+0+0+0+12+12+12+12+12+12}{12} \\Mean=6\\Median=\frac{12+0}{2}=6

<u>University of Maryland</u>

1 player scores 58 points per game,

1 player scores 14 points per game,

The rest(10) of the players score 0 points per game.

The Scores are: 0,0,0,0,0,0,0,0,0,0,14,58

Mean=\frac{0+0+0+0+0+0+0+0+0+0+14+58}{12} \\Mean=6\\Median=\frac{0+0}{2}=0

<u> Dartmouth College</u>

4 players score 5 points per game,

4 players score 6 points per game,

4 players score 7 points per game.

The Scores are: 5,5,5,5,6,6,6,6,7,7,7,7

Mean=\frac{5+5+5+5+6+6+6+6+7+7+7+7}{12} \\Mean=6\\Median=\frac{6+6}{2}=6

The following applies:

(B) At Maryland, the mean number of points per player per game is greater than the median number of points per player per game.

(D)The mean number of points per player per game is the same at all 3 schools.

7 0
2 years ago
The vertices of rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0). what is the perimeter of the rhombus?
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Answer: 20 unit.

Step-by-step explanation:

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By the property of rhombus,

de =  ef = fg = gd = 5 unit.

Thus, the perimeter of the given rhombus defg = de +  ef + fg + gd = 5+5+5+5 = 20 unit

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2 years ago
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