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tamaranim1 [39]

1 year ago

14

A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. Two marbles are chosen from

the bag. What expression would give the probability that one marble is yellow and the other marble is red? P(Y and R) = P(Y and R) = P(Y and R) = P(Y and R) = -----We Have Reached 50 Thanks!!! The 50pts Question Will Be Up Tomorrow Around 8:00am - 10:00am Stay Toon!!!!!!!!!!

2 answers:

Kryger [21]1 year ago

8 0

Answer:

The expression would give the probability that one marble is yellow and the other marble is red is,

$P(Y\cdot R\ And\ R\cdot Y)=P(Y)P(R)+P(R)P(Y)$

Step-by-step explanation:

A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. So in total there are 25 marbles.

Hence,

Probability of getting yellow ball = $P(Y)=\dfrac{8}{25}$

Probability of getting red ball = $P(R)=\dfrac{5}{25}$

Probability that one marble is yellow and the other marble is red is,

$P(Y\cdot R\ And\ R\cdot Y)=P(Y)P(R)+P(R)P(Y)=\dfrac{8}{25}\cdot \dfrac{5}{25}+\dfrac{5}{25}\cdot \dfrac{8}{25}=0.128$

elena-14-01-66 [18.8K]1 year ago

7 0

Y and r: 0.04 or 4% ---------------------

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