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Anettt [7]
2 years ago
15

A mouse traveled a total distance of 3/24 of a mile in a maze over the past three hours the mouse travel the same distance each

hour to determine the distance that the mouse traveled age our map reformed the calculations below he concluded that the mouse travel 3/8 of a mile each hour what is Matt’s error
Mathematics
1 answer:
alexgriva [62]2 years ago
8 0

Answer:

Total distance mouse traveled in 3 hours = \frac{3}{24} of a mile

The mouse traveled the same distance in each hour. So in order to find the distance covered in 1 hour we have to divide the distance covered in 3 hours by 3. This will give us the distance that the mouse traveled in one hour.

So, the distance traveled in one hour will be = \frac{3}{24} \div 3 = \frac{3}{24} \times \frac{1}{3} =\frac{1}{24} of a mile

The error which Matt made was that he divided only the denominator of the expression by 3, this probably was a calculation error.

Correct conclusion will be: Mouse travel 1/24 of a mile each hour

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A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
2 years ago
World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of
Sunny_sXe [5.5K]

Answer:

a) W(t) = 371(1.168)^{t}

b) Wind capacity will pass 600 gigawatts during the year 2018

Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

(1.168)^{t} = 1.61725

We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

7 0
2 years ago
If 2^2008 – 2^2007 - 2^2006 + 2^2005 = k * 2^2005 then the value of k is equal to​
scZoUnD [109]

Step-by-step explanation:

Maths

Bookmark

if 2

2008

−2

2007

−2

2006

+2

2005

=k ⋅2

2005

then the value of k is equal to

Answer

Correct option is

B

3

2

2008

−2

2007

−2

2006

+2

2005

=k⋅2

2005

⇒[2

2008

−2

2006

]−[2

2007

−2

2005

]=k⋅2

2005

⇒2

2006

(2

2

−1)−2

2005

(2

2

−1)=k⋅2

2005

⇒3(2

2006

−2

2005

)=k⋅2

2005

⇒3[2

2005

(2−1)]=k⋅2

2005

⇒3(2

2005

)=k⋅2

2005

On comparing, we get

k=3

Hence, Option B is correct.

5 0
1 year ago
Read 2 more answers
Sofia measures the length of her car as 16 feet. What is the greatest possible error? ______ feet What is the margin of error? _
Genrish500 [490]

Answer:

Sofia measures the length of her car as 16 feet.

What is the greatest possible error?  

<h2> ⇒ 0.5 feet </h2>

What is the margin of error?  

<h2> ⇒ 15.5  TO  ⇒ 16.5 feet</h2>

Step-by-step explanation:


3 0
2 years ago
Factor 125x9 + 64. (5x3 – 4)(25x6 + 20x3 + 16) (5x3 – 4)(25x3 + 20x3 + 16) (5x3 + 4)(25x6 – 20x3 + 16) (5x3 + 4)(25x3 – 20x3 + 1
SSSSS [86.1K]
(5x^3 + 4)(25x^6 - 20x3 +16)  remember factoring the cubes?
4 0
2 years ago
Read 2 more answers
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