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2 years ago

Which graph represents the hyperbola = 1?

Mathematics

2 answers:

Andrews [41]2 years ago

6 0

Answer:

131

Step-by-step explanation:

We have to find the graph of the hyperbola whose equation is given as:.We know that the general equation of the hyperbola is given by:where the focus of the hyperbola are at the points:(a,0) and (-a,0).Hence, the focus of the given hyperbola are the points:(3,0) and (-3,0).The figure of the hyperbola is attached to the figure.

liberstina [14]2 years ago

6 0

Answer:

Step-by-step explanation:

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Find the perimeter of $\triangle CDE$ . Round your answer to the nearest hundredth. A trapezoid A B C D is plotted on a coordina

guapka [62]

Answer:

The answer is below

Step-by-step explanation:

We are asked to find the perimeter of triangle CDE. The perimeter of a shape is simply the sum of all its sides, hence:

Perimeter of tiangle CDE = |CD| + |DE| + |CE|

Given that C(4, -1), D(4, -5), E(2, -3).

The distance between two points $X(x_1,y_1)\ and\ Y(x_2,y_2)$ is given as:

$|XY|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Therefore the lengths of the triangle are:

$|CD|=\sqrt{(4-4)^2+(-5-(-1))^2} =4\ units\\\\|DE|=\sqrt{(2-4)^2+(-3-(-5))^2} =2.83\ units\\\\|CE|=\sqrt{(2-4)^2+(-3-(-1))^2} =2.83\ units$

Perimeter of CDE = 4 + 2.83 + 2.83 = 9.66 units

8 0

2 years ago

Pepper jackie used a precision hydrometer to perform an experiment at 2 local restaurants to determine which restaurant uses the

NISA [10]

Answer:

. ALL of the beverages at The Zest Nest ARE LIKELY to contain 46 grams of sugar or less, but NONE of the beverages at Jim's juice joint ARE LIKELY to contain LESS THAN 46 grams of sugar.

3 0

2 years ago

Read 2 more answers

In the right △ABC with m∠C=90°, m∠B=75°, and AB = 12 cm. Find the area of △ABC.

azamat

Given that ABC is a right angle triangle with m∠C=90°, m∠B=75° and AB=12cm.

Area of triangle =

So we need to find BC,AC now.

To find them let us take sinB and cosB.

SinB =

BC = 12* cos B = 12* cos 75

So, area =

= 72*sin(75)*cos(75)

= 36*(2sin(75)cos(75))

= 36*sin(150) = 18

Hence area of triangle is 18

Hope this helps tbh sorry I was a little late btw (:

7 0

2 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

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2 years ago

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C lejgjjf484885845886

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