All categories

2 years ago

Which graph represents the hyperbola = 1?

Mathematics

2 answers:

Andrews [41]2 years ago

6 0

Answer:

131

Step-by-step explanation:

We have to find the graph of the hyperbola whose equation is given as:.We know that the general equation of the hyperbola is given by:where the focus of the hyperbola are at the points:(a,0) and (-a,0).Hence, the focus of the given hyperbola are the points:(3,0) and (-3,0).The figure of the hyperbola is attached to the figure.

liberstina [14]2 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Two parallel lines are crossed by a transversal. What is the value of D?

Sliva [168]

Answer:c

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is 40653230000000 in standard form

lorasvet [3.4K]

4065323 × 10 to the senventh power?

3 0

2 years ago

Suppose A = {x |x ≤ −2, x ≥ 3} and B = {x | −1 ≤ x < 5}. Which statement is true?

vagabundo [1.1K]

A.A∪ B is real numbers

3 0

2 years ago

Two production lines are used to pack sugar into 5 kg bags. Line 1 produces twice as many bags as does line 2. One percent of ba

enyata [817]

Answer:

P(Bag is Defective) = 0.0167

Step-by-step explanation:

Line 1 produces twice as many bags as line 2. Let x be the number of bags produced by line 2.

No. of bags produced by line 2 = x

No. of bags produced by line 1 = 2x

Probability that the bag has been produced by line 1 can be written as:

P(Line 1) = No. of bags produced by line 1/Total no. of bags

= 2x/(x+2x)

= 2x/3x

P(Line 1) = 2/3. Similarly,

P(Line 2) = x/3x

P(Line 2) = 1/3

1% bags produced by line 1 are defective so the probability of line 1 producing a defective bag is:

P(Defective|Line 1) = 0.01

3% of bags from line 2 are defective, so:

P(Defective|Line 2) = 0.03

b. The probability that the chosen bag is defective can be calculated through the conditional probability formula:

P(A|B) = P(A∩B)/P(B)

P(A∩B) = P(A|B)*P(B)

The chosen defective bag can be either from line 1 or from line 2. So, the probability that the chosen bag is defective is:

P(Bag is Defective) = P(Defective and from Line 1) + P(Defective and from Line 2)

= P(D∩Line 1) + P(D∩Line 2)

= P(Defective|Line 1)*P(Line 1) + P(Defective|Line 2)*P(Line 2)

= (0.01)*(2/3) + (0.03)(1/3)

P(Bag is Defective) = 0.0167

7 0

2 years ago

Read 2 more answers

The graphs below shows some properties of regular

Dmitrij [34]

Corrected Question

The graphs below shows some properties of regular polygons. When compared with the independent variable, how many of the other three columns of the graphs represent a linear relationship?

(A)0 (B)1 (C)2 (D)3

Answer:

Step-by-step explanation:

Given the independent variable (Number of sides of the polygon), we notice that out of the three other columns:

Number of Diagonals