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2 years ago

One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared

Mathematics

1 answer:

AfilCa [17]2 years ago

6 0

Answer:

29119.66666...+14561.3333...=43681, 209ft^2, not square feet.

Step-by-step explanation:

"One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared"

Ok, so this is a tricky one- 209 feet squared, not 209 square feet, therefore the area is 209^2, or 43,681.

Next, let's define our variables-

x= the "other side"

z= 3 feet shorter than twice side

We can now make these (useful) equations

z=2x-3

43681= (2x-3)+x

We will focus on the latter for now-

Simplify

43681= (2x-3)+x

43681= 2x-3+x

43681= 3x-3

43684=3x

14561.3333...=x

z=2x-3

z=2*(14561.3333)-3

z=29119.66666....

29119.66666...+14561.3333...=43681

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Lin multiplies 7/8 times a number. The product is less than 7/8. Which could be Lin’s number?

RSB [31]

Answer:

So, the number that Lin multiplied by 7/8 MUST be less than 1. This is evident, as any positive number multiplied by a number less than 1 will decrease, doesn't matter if its a negative or positive number.

Step-by-step explanation:

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2 years ago

It is 1 1/4 miles from Ahmed’s house to school. How far does Ahmed’s travel in 5 days walking to school and back

Sauron [17]

Ahmed travel $12\frac{1}{2}$ miles in 5 days walking to school and back.

Step-by-step explanation:

Distance from house to school = $1\frac{1}{4}$ miles

Distance from school to house = $1\frac{1}{4}$ miles

Total distance in 1 day = $1\frac{1}{4}+1\frac{1}{4}=\frac{5}{4}+\frac{5}{4}$

Total distance in 1 day = $\frac{5+5}{4}=\frac{10}{4}$

Distance traveled in 5 days = $5*\frac{10}{4}=\frac{50}{4}$

Distance traveled in 5 days = $\frac{25}{2}=12\frac{1}{2}$

Ahmed travel $12\frac{1}{2}$ miles in 5 days walking to school and back.

Keywords: fraction, addition

Learn more about fractions at:

#LearnwithBrainly

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2 years ago

Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y

lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

Translate one of the two circles so that they have the same center
Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well

Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

Start with circle X and radius r
Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
Scale the radius of circle X' until it becomes $s$ . This new circle, say X'', is similar to X' because you only scaled it