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n200080 [17]
2 years ago
8

Perfume is sold in two different sizes of bottle. The 80ml bottle is priced at £55. The 50ml bottle is usually priced at £45, bu

t is on special offer. If you buy one 50ml bottle of perfume you can get a second for half price.
By calculating the price per ml determine which offers the best value for money the 80ml or two 50ml bottles ? You must show your working .
Mathematics
1 answer:
Nadya [2.5K]2 years ago
8 0
1ml of 80ml bottle: 55/80 = 0.6875 pence

1ml of 50ml bottle: 45/50 = 0.9 pence

If no special offer the first bottle is a better value for money.

Since special offer though, you'd be buying;

50ml bottle £45 + another 50ml £22.5 = £67.5 in

which case 1ml would cost;

67.5/100 = 0.675 pence. Hence buying 2x50ml

bottle would be a better value.


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A theatre has the capacity to seat people across two levels, the Circle and
andriy [413]

Answer: 76.19\%

Step-by-step explanation:

<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and \frac{2}{3} of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>

Let be "s" the total number of seats in the Stalls.

The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is 2:5.

Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

\frac{2}{5}=\frac{528}{s}

Solving for "s", we get:

s*\frac{2}{5}=528\\\\s=528*\frac{5}{2}\\\\s=1,320

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:

Total=1,320\ seats+528\ seats=1,848\ seats

 We know that \frac{2}{3} of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

(1,320)(\frac{2}{3})=880

Therefore, the total number of seats that were occupied las Friday is:

Total\ occupied=880\ seats+528\ seats=1,408\ seats

Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

\frac{100}{1,848}=\frac{p}{1,408}

Solving for "p", we get:

(1,408)(\frac{100}{1,848})=p\\\\p=76.19\%

8 0
2 years ago
From Environment Canada: "Our experts on weather and climate have combed through 45 years of weather records, and determined the
miskamm [114]
Hat grade are u? I'm just asking cause the formulas are going with grade I could help if u want me too
7 0
2 years ago
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If we were to make a poset of the form (A, |), where is the symbol for divisibility, which of the following sets A would yield a
Marrrta [24]

Answer:

IV. A+{1, 2, 3, 6, 12}

Step-by-step explanation:

The set of natural numbers form a poset number under relation of > or =. The discrete variables are used to form a poset. The symbols for divisibility in poset form are when an integer is divided by the variable without integer. The correct answer is therefore 4th option.

5 0
2 years ago
Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1
astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

x^{2} - 24 = 1

Given that resulting expression is a second order polynomial of the form x^{2} - a^{2}, there are two real and distinct solutions. Roots of the expression are:

x_{1} = -5 and x_{2} = 5.

Now, it is also required to determine which part of the interval (x_{1}, x_{2}) is equal to a number greater than zero (positive). That is:

x^{2} - 24 > 0

x^{2} > 24

x < -4.899 and x > 4.899.

Therefore, exists two sub-intervals: [-5, -4.899] and \left[4.899,5\right]. Besides, x^{2} - 24 > y = 1 in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx

A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx

A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}

A = 2.525 -2.474+9.798 + 2.525 - 2.474

A = 9.9\,units^{2}

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

4 0
2 years ago
Vicki has 210 baseball cards and buys an additional 15 cards every week. Jeb has 275 baseball cards and buys an additional 10 ca
Hitman42 [59]

Answer:

11 weeks

Step-by-step explanation:


5 0
2 years ago
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