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Black_prince [1.1K]

2 years ago

14

Sarah invested $800 in an account paying an interest rate of 3.5% compounded quarterly. Assuming no deposits or withdrawals are

made, how much money, to the nearest cent, would be in the account after 8 years?

1 answer:

Korolek [52]2 years ago

5 0

Answer:

$ 1,057.22

Step-by-step explanation:

A = $ 1,057.22

A = P + I where

P (principal) = $ 800.00

I (interest) = $ 257.22

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What is the solution to 2 log Subscript 9 Baseline (x) = log Subscript 9 Baseline 8 + log Subscript 9 Baseline (x minus 2) x = n

Kaylis [27]

Answer:

$\large\boxed{\large\boxed{x=4}}$

Step-by-step explanation:

The equation to solve is:

$2\log_9 x=\log_9 8+\log_9 (x-2)$

1. <u>On the left-hand side </u>use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"

Thus, the left-hand side is:

$2\log_9 x=\log_9 x^2$

2. On the <u>right-hand side</u> use "The sum of two logarithms with the same base is the logarithm of the product":

Then, on the right-hand side:

$\log_9 8+\log_9 (x-2)=\log_9 8(x-2)$

3. <u>Make them equal</u>:

$\log_9 x^2=\log_9 8(x-2)$

4. Since the two functions are the same, <u>make the arguments equal</u>:

$x^2=8(x-2)$

5. <u>Solve the equation</u>:

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2 years ago

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What proportion of these candy bars have more than 300 calories per serving? (Round your answer to two decimal places.)

Hatshy [7]

Answer: 0.12

Step-by-step explanation:

There are 65 candy bars. Out of that;

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1 candy bar has 350 to 400 calories

4 candy bars have 400 to 450 calories

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The total proportion out of 65 candy bars that have over 300 calories is;

= ( 2 + 1 + 4 + 1) / 65

= 8/65

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2 years ago

7 girls audition for 12 roles in a school play. What is the probability that at least 2 of the girls audition for the same part?

Sophie [7]

Answer:

Step-by-step explanation:

This is one minus the probability that all the girls audition for different roles. The total number of ways of assigning roles to the girls is 12^7, because to each of the 7 girls, you have a choice of 12 roles.

Then if each girl is to receive a different role, then there are 12!/5! possibilities for that. If you start assigning roles to the girls, then for the first girl, there are 12 choices, but for the next you have to choose one of the 11 different ones, so 11 for the next, and then one of the 10 remaining for the next etc. etc., and this is 12*11*10*...*6 = 12!/(12-7)! =12!/5!

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(12!/5!)/12^7 = 12!/(12^7 5!)

Then the probability that two or more girls addition for the same part is the probability that not all the girls are assigned different roles, this is thus:

1 - 12!/(12^7 5!)

6 0

2 years ago