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2 years ago

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A manufacturing company measures the weight of boxes before shipping them to the customers. Assume that the weights of boxes are

normally distributed with mean 90 lbs and standard deviation 24 lbs. a) Find the probability that a randomly selected box will exceed 94 lbs. b) If a sample of 36 boxes is randomly selected, find the probability that the average of the boxes exceeds 94 lbs.

1 answer:

Sedaia [141]2 years ago

3 0

Answer:

24

Step-by-step explanation:

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The balanced scale represents the equation: 3x + 1 = x + 3

Afina-wow [57]

<u>Given</u>:

The given balanced scale is represented by the equation

$3x+1=x+3$ ----- (1)

We need to determine the process that balance the scale.

<u>Process to balance the scale:</u>

Given that the if one x block is subtracted from the right side and three numbered blocks are subtracted from the left side.

Thus, the equation (1) becomes

$(3x+1)-3=(x+3)-x$

$3x-2=3$ ----- (2)

Now, to balance the scale, let us subtract one block x from the left side and subtract three numbered blocks from the right side.

Thus, the equation (2) becomes,

$(3x-2)-x=3-3$

$2x-2=0$ ------ (3)

Thus, the equation (3) is the same as the equation (1).

Hence, the process required to balance the scale is to subtract one x block from the left side and subtract three numbered blocks from the right side.

Therefore, Option B is the correct answer.

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2 years ago

It costs $23 per hour plus a flat fee of $16 for a plumber to make a house call. What is the equation of the form y = mx + b for

Ad libitum [116K]

D is the best choice because y would be the total amount of money he would have to pay. X would be the amount of hours he uses the phone and the hourly fee is 23 so it would be 23x. the flat fee was 16 so you just add that on to the hourly fee. The whole equation should be y = 23x + 16

7 0

2 years ago

Read 2 more answers

(iii) Find the smallest whole number h such that<br>4704/h<br>is a cube number.<br>

yan [13]

Answer:

$h=588$

Step-by-step explanation:

Given the fraction $\dfrac{4,704}{h}$

Consider its numerator and factor it:

$4,704=2^5\cdot 3\cdot 7^2$

You cann not take the cube root from $3, 7^2, 2^5,$ you can only take the cube root from $2^3$ , then the smallest whole number $h$ such that $\dfrac{4,704}{h}$ is a cube number is

$h=2^2\cdot 3\cdot 7^2=4\cdot 3\cdot 49=588$

When $h=588,$

$\dfrac{4,704}{588}=8=2^3$

6 0

2 years ago

On monday maggie ran n miles on tuesday she ran 90% of the number of miles she ran on monday and on tuesday she ran 50% of the n

kari74 [83]

Answer:

let number of mile on monday be x

tuesday = 9/10 of x

wednesday = 9/20 of x

Step-by-step explanation:

tues = 90/100=9/10

wednes = 50/100 * 90/100 * x

wednes = 9/20 of x

3 0

2 years ago

F(x)=3x 2 +9f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 9 and g(x)=\dfrac{1}{3}x^2-9g(x)= 3 1 x 2

34kurt

Answer:

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

$g(f(x)) = 3x^4 + 18x^2 + 18$

<em>f(x) and g(x) and not inverse functions</em>

Step-by-step explanation:

Given

$f(x) = 3x^2 + 9$

$g(x) = \dfrac{1}{3}x^2 - 9$

Required

Determine f(g(x))

Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

$f(x) = 3x^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9$

Expand Brackets

$f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = \frac{1}{3}x^4 - 9x^2 - 9x^2 + 243 + 9$

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

Calculating g(f(x))

$g(x) = \dfrac{1}{3}x^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9$

$g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9$

Expand Brackets

$g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9$

$g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9$

$g(f(x)) = 3x^4 + 18x^2 + 18$

Checking for inverse functions

$f(x) = 3x^2 + 9$

Represent f(x) with y

$y = 3x^2 + 9$

Swap positions of x and y

$x = 3y^2 + 9$

Subtract 9 from both sides

$x - 9 = 3y^2 + 9 - 9$

$x - 9 = 3y^2$

$3y^2 = x - 9$

Divide through by 3

$\frac{3y^2}{3} = \frac{x}{3} - \frac{9}{3}$

$y^2 = \frac{x}{3} - 3$

Take square root of both sides

$\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}$

$y = \sqrt{\frac{x}{3} - 3}$

Represent y with g(x)

$g(x) = \sqrt{\frac{x}{3} - 3}$

Note that the resulting value of g(x) is not the same as $g(x) = \dfrac{1}{3}x^2 - 9$

<em>Hence, f(x) and g(x) and not inverse functions</em>

4 0

2 years ago