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ad-work [718]
2 years ago
7

A manufacturing company measures the weight of boxes before shipping them to the customers. Assume that the weights of boxes are

normally distributed with mean 90 lbs and standard deviation 24 lbs. a) Find the probability that a randomly selected box will exceed 94 lbs. b) If a sample of 36 boxes is randomly selected, find the probability that the average of the boxes exceeds 94 lbs.
Mathematics
1 answer:
Sedaia [141]2 years ago
3 0

Answer:

24

Step-by-step explanation:

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Beaker A contains 4 1/3 fluid ounces, while beaker B contains 4 3/10 of water . Which beaker has the smaller amount of water
kirill [66]
Beaker  A contains more water.
First,find equivalent fraction.
Next,compare the amounts you will see Beaker A contains more water.
Therefore,Beaker A contains more water.
8 0
2 years ago
Let P2 be the vector space of all polynomials of degree 2 or less, and let H be the subspace spanned by 10x2+4xâ1, 3xâ4x2+3, and
lord [1]

I suppose

H=\mathrm{span}\{10x^2+4x-1,3x-4x^2+3,5x^2+x-1\}

The vectors that span H form a basis for P_2 if they are (1) linearly independent and (2) any vector in P_2 can be expressed as a linear combination of those vectors (i.e. they span P_2).

  • Independence:

Compute the Wronskian determinant:

\begin{vmatrix}10x^2+4x-1&3x-4x^2+3&5x^2+x-1\\20x+4&3-8x&10x+1\\20&-8&10\end{vmatrix}=-6\neq0

The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of H is 3.

  • Span:

Write an arbitrary vector in P_2 as ax^2+bx+c. Then the given vectors span P_2 if there is always a choice of scalars k_1,k_2,k_3 such that

k_1(10x^2+4x-1)+k_2(3x-4x^2+3)+k_3(5x^2+x-1)=ax^2+bx+c

which is equivalent to the system

\begin{bmatrix}10&-4&5\\4&3&1\\-1&3&-1\end{bmatrix}\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}a\\b\\c\end{bmatrix}

The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives

\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}-\dfrac{6a-11b+19c}3\\\dfrac{3a-5b+2c}3\\\dfrac{15a-26b+46c}3\end{bmatrix}

so the vectors do span P_2.

The vectors comprising H form a basis for it because they are linearly independent.

4 0
2 years ago
What is the y-intercept of the function,represented by the table of values below?
Hitman42 [59]

Answer:

8

Step-by-step explanation:

So the y-intercept is not given by your table because there is no x that is listed as 0.

But don't fret; we can still find it.

Let's see if the function is linear by seeing if we have the same slope per two points in the table.

For the first pair ( the points (-2,16) and (1,4) ), x increased by 3 and the y decreased by 12 so the slope there is -12/3=-4.

Now looking at the next pair ( the points (1,4) and (2,0) ), x increased by 1 while y decreased by 4 so the slope is -4/1=-4.

So the function appears to be linear.

So the slope-intercept form of a line is y=mx+b where m is slope and b is y-intercept.

We already found the slope from earlier which is m=-4.

So the equation so far is y=-4x+b.

Now to find b, the y-intercept, we need to use a point (x,y) on the line along with y=-4x+b.

Let's see my favorite on the list of points is (2,0).

y=-4x+b with (x,y)=(2,0)

0=-4(2)+b

0=-8+b

8=b

So the y-intercept is 8.

8 0
2 years ago
Read 2 more answers
The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
Kruka [31]

Answer:

The probability that exactly 15 defective components are produced in a particular day is 0.0516

Step-by-step explanation:

Probability function : P(X=x)=e^{-\lambda} \frac{\lambda^x}{x!}

We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.

So,\lambda = 20

we are supposed to find the probability that exactly 15 defective components are produced in a particular day

So,x = 15

Substitute the values in the formula :

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=0.0516

Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516

8 0
2 years ago
Kristen is 64 inches tall, and she stands 12 feet away from a streetlight. If she casts an 82-inch-long shadow, how tall is the
o-na [289]

Answer:

176.39 inches or

14.70 feet

Step-by-step explanation:

Consider the right triangle made by Kristen, ground and shadow.

This triangle has one leg as 64 inches.

Next consider the right triangle formed by street light, ground upto shadow tip.

The two triangles have common angle of elevation and also another angle as 90 degrees.

Hence the two triangles would be similar

Also if A is the angle made by hypotenuse of both triangles with the ground we have

tanx=\frac{64}{82}

This value also equals by bigger triangle as

tanx=\frac{h}{82+12(12)}=\frac{h}{226}

From these two we get

h = height of street light =\frac{226(64)}{82} =176.39

6 0
2 years ago
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