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Andrew [12]
1 year ago
11

Diep buys a loaf of bread 65 centimeters long. For lunch every afternoon, he cuts 15 centimeters of bread for his sandwich. Diep

wants to determine the length of the loaf of bread, l, after d days. What is the equation of the scenario? Is the graph of the equation continuous or discrete? a) l = 65 – 15d; discrete b) l = 65 – 15d; continuous c) 65 = l – 15d; discrete d) 65 = l – 15d; continuous
Mathematics
2 answers:
Vladimir [108]1 year ago
7 0

Answer:

a

Step-by-step explanation:

After d days, the loaf of bread is 65 - 15d long.

l = 65 - 15d.

The graph is discrete, as he cannot cut the bread for 1.5 days, or cut 5cm of the bread off.

ki77a [65]1 year ago
6 0

Answer:

l = 65 – 15d; discrete

Step-by-step explanation:

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8 dollars is the answer
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Eiko is wearing a magic ring that increases the power of her healing spell by 30\%30%30, percent. Without the ring, her healing
Veronika [31]

Answer:

(13/10)H

got it on khan academy brainliest pls thx uwu

Remember that 30% in fraction form is 33/100

The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:

(30/100)H

And since it would add that to the current total we can right the current total as:

(100/100)H

So our equation would be

=(30/100)H + (100/100)H

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2 years ago
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Aramp is 17 feet long, rises 8 feet above the floor, and covers a horizontal distance of 15 feet, as shown in the figure.
bonufazy [111]

Answer:

The ratio of Tan B is

\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}

OR

\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}

Step-by-step explanation:

In Right Angle Triangle ABC

angle C = 90°

AB = Ramp = 17 feet

BC =Horizontal distance = 15 feet

AC = Height from floor = 8 feet

To Find:

Ratio of Tan B = ?

Solution:

In Right Angle Triangle ABC By Tangent Identity we have

\tan B= \dfrac{\textrm{side opposite to angle B}}{\textrm{side adjacent to angle B}}

Substituting the given values we get

\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}

OR

\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}

5 0
2 years ago
A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w
sveta [45]

Answer:

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for business  

\hat p_A =\frac{75}{400}=0.1875 represent the estimated proportion for Business

n_A=400 is the sample size required for Business

p_B represent the real population proportion for non Business

\hat p_B =\frac{137}{500}=0.274 represent the estimated proportion for non Business

n_B=500 is the sample size required for non Business

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

7 0
1 year ago
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