If ray NP bisects <MNQ, m<MNQ=(8x+12)°, m<PNQ=78°, and m<RNM=(3y-9)°, find the value of x and y
1 answer:
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Answer:
Step-by-step explanation:
The equation of the sphere, centered a the origin is given by . Then, when z=4, we get
.
This equation corresponds to a circle of radius in the x-y plane
c) We will use the previous analysis to define the limits in cartesian and polar coordinates. At first, we now that x varies from up to
. This is by taking y =0 and seeing the furthest points of x that lay on the circle. Then, we know that y varies from
and
, this is again because y must lie in the interior of the circle we found. Finally, we know that z goes from 4 up to the sphere, that is , z goes from 4 up to
Then, the triple integral that gives us the volume of D in cartesian coordinates is
.
b) Recall that the cylindrical coordinates are given by , where r corresponds to the distance of the projection onto the x-y plane to the origin. REcall that
. WE will find the new limits for each of the new coordinates. NOte that, we got a previous restriction of a circle, so, since
goes from 0 to
. Also, note that r goes from the origin up to the border of the circle, where r has a value of 4\sqrt[]{3}. Finally, note that Z goes from the plane z=4 up to the sphere itself, where the restriction is \sqrt[]{64-r^2}. So, the following is the integral that gives the wanted volume
. Recall that the r factor appears because it is the jacobian associated to the change of variable from cartesian coordinates to polar coordinates. This guarantees us that the integral has the same value. (The explanation on how to compute the jacobian is beyond the scope of this answer).
a) For the spherical coordinates, recall that . where
is the angle of the vector with the z axis, which varies from 0 up to pi. Note that when z=4, that angle is constant over the boundary of the circle we found previously. On that circle. Let us calculate the angle by taking a point on the circle and using the formula of the angle between two vectors. If z=4 and x=0, then y=4
if we take the positive square root of 48. So, let us calculate the angle between the vector
and the vector b =(0,0,1) which corresponds to the unit vector over the z axis. Let us use the following formula
Therefore, over the circle, . Note that rho varies from the plane z=4, up to the sphere, where rho is 8. Since
, then over the plane we have that
Then, the following is the desired integral
where the new factor is the jacobian for the spherical coordinates.
d ) Let us use the integral in cylindrical coordinates
Note that we can split the integral since the inner part does not depend on theta on any way. If we use the substitution then
, then
Answer:
a)
b) We are uncertain
c) It will change significantly
Step-by-step explanation:
a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.
Since we assume that the variances are equal, we use the pooled variance given as
,
where .
The mean difference .
The confidence interval is
b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.
c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.