we know that
The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.
In this problem
![21\°=\frac{1}{2}[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=21%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20RU-arc%5C%20SU%5D)
Solve for the measure of arc SU
![42\°=[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Barc%5C%20RU-arc%5C%20SU%5D)


therefore
the answer is
The measure of the arc SU is 
Answer:
See the solutions below
Step-by-step explanation:
Given data
Distance = 24.6km
in meters= 24.6*1000= 24600m
time= 30 minutes
in seconds= 30*60= 1800
int hours= 0.5 hour
speed of the particle in
(i) km/h= 24.6/0.5= 49.2 km/h
(ii) m/s.= 24600/ 1800= 13.66 m/s
Answer:
99.87% of the store’s total delivery orders will be delivered to consumers with charge
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If a pizza store’s policy is, "Orders delivered within one hour or they’re free!", what percentage of the store’s total delivery orders will be delivered to consumers with charge?
Within one hour, which is 60 minutes. So this is the pvalue of Z when X = 60.



has a pvalue of 0.9987
99.87% of the store’s total delivery orders will be delivered to consumers with charge
Angle AQB is x = 90
Angle ASB is x = 90
Angle ALB is x = 90
Angle ATB is x = 90
Angle ARB is x = 90
<span>BWD is x < 90</span>