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1 year ago

Factor the GCF: −6x4y5 − 15x3y2 + 9x2y3

1 answer:

8 0

−24xy^5−15x×3y^2+9x×2y^3

−24xy^5−45xy^2+9x×2y^3
−24xy^5−45xy^2+18xy^3

Hope i helped^-^

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A Climbing Gym charges $10 to climb each day. A pair of Climbing shoes cost $84. It cost $169 to buy 6 days of climbing, one pai

yaroslaw [1]

Cost of 6 days climbing = $10 * 6 = $60
Cost of one pair of shoes = $84
Total cost = $169

So, cost of one harness = $169 - $(84+60)
harness = $169 - $144 = $25

So, your final answer is $25

8 0

2 years ago

Workers have packed 1,400 glasses in 7 boxes. If they pack 3 more boxes, how many glasses will they have packed in all?

Alexandra [31]

2000

1box = 1400/7 = 200
200×3=600
1400+600=2000

Step-by-step explanation:
Given :Workers have packed 1,400 glasses in 7 boxes.
To Find :If they pack 3 more boxes, how many glasses will they have packed in all?
Solution:
Workers packed no. of glasses in 7 boxes = 1400
Workers packed no. of glasses in 1 box =
Workers packed no. of glasses in 3 boxes =
=
So, initially they packed 1400 glasses
If they pack 3 more boxes so, the pack 600 glasses more
So, The total no. of glasses have packed by workers = 1400+600 = 2000
Hence they have packed 2000 glasses in all.

5 0

2 years ago

15 PINTS!!!!!!!!! PLZ HELP!!!!!!!! The linear function f(x) = 0.5x + 80 represents the average test score in your math class, wh

Stells [14]

Answer:

Part A: The test average for the math class after completing 2 tests is 81

Part B: The test average for the science class after completing 2 tests is 83

Part C: The science class had the higher average test score after completing the test 4.

Step-by-step explanation:

The average test score for math class is given by the linear function, f(x) = 0.5·x + 80

The data for the average test score for science g(x) are;

x, q(x)

1, 81

2, 83

3, 85

Part A: The average test score for math after completing test 2 is given as follows;

f(2) = 0.5×2 + 80 = 81

∴ The test average for the math class after completing 2 tests = 81

Part B:

The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83

∴ The test average for the science class after completing 2 tests = 83

Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82

For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;

Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87

Since g(4) > f(4) the science class had the higher average test score after completing the test 4.

4 0

1 year ago

An architect designs a castle tower for a new attraction at a popular amusement park. Blueprints of the tower, which is in the s

marin [14]

Answer:

The surface area of the tower is 5,218.1 m²

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Height of the blueprint = 47 cm

Length of the blueprint = 23 cm

Width of the blueprint = 25 cm

Scale factor 1 : 96

2. Calculate the actual surface area of the tower and enter your answer in square meters with two decimal places.

Let's calculate the measurements of the actual tower:

Height of the blueprint = 47 * 96 = 4,512 cm = 45.12 m

Length of the blueprint = 23 * 96 = 2,208 cm = 22.08 m

Width of the blueprint = 25 * 96 = 2,400 cm = 24 m

Now, let's calculate the surface area of the tower, this way:

Surface area of the tower = 2* (24 * 22.08) + 2 * (45.12 * 22.08) + 2 * (45.12 * 24)

Surface area of the tower = 1,059.84 + 1,992.5 + 2,165.76

Surface area of the tower = 5,218.1 m²

4 0

2 years ago

Alice has a 4-inch by 5-inch photo of your school’s championship girls’ ice hockey team. To celebrate their recent

Pachacha [2.7K]

Alice should pick the enlarged-photo with dimensions of 8-inch by 10-inch.

Step-by-step explanation:

Step 1:

In order for a part of the photo to not be cut off, the enlarged photo's dimensions should be of a constant ratio with the original photo's dimensions.

We divide the dimensions of the enlarged-photo with the dimensions of the original photo to check which has a constant ratio.

Step 2:

The original photo was a 4-inch by 5-inch photo.

Option 1 is 7-inch by 9-inch, so the ratios are

$\frac{7}{4} = 1.75, \frac{9}{5} = 1.8.$ The ratios are different so this cannot be the enlarged photo's dimensions.

Option 2 is 8-inch by 10-inch, so the ratios are

$\frac{8}{4} = 2, \frac{10}{5} = 2.$ The ratios are the same so this can be the enlarged photo's dimensions.

Option 3 is 12-inch by 16-inch, so the ratios are

$\frac{12}{4} = 3, \frac{16}{5} = 3.2.$ The ratios are different so this cannot be the enlarged photo's dimensions.

So the enlarged-photo with dimensions of 8-inch by 10-inch should be picked.

7 0

2 years ago