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ELEN [110]
1 year ago
8

an employee adds 160 fluid ounces of chemical to a feature that holds 120,000 gallons of water. did the employee add yhe correct

amount?
Mathematics
1 answer:
Hitman42 [59]1 year ago
5 0
We are given a volume of 160 fluid ounces of chemical which is added to a container that holds 120,000 gallons of water. Assuming that the chemical has the same density as water, we just need to convert 120,000 gallons to ounces.

A conversion factor is taken from literature, 1 gallon is equivalent to 128 fluid ounces. So 160 fluid ounces is only 1.25 gallons, thus occupying minimal space in the container. The employee could add more of the chemical in the container. He can actually add 15360000 fluid ounces in total. 
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When does a payday loan typically mature?
marin [14]

Payday loans which are also called short term loans or sometimes referred to as cash advances. These types of loans are based upon the borrower’s employment payroll records. Since this is based upon the payroll records of the borrower that means that it will mature after the borrower’s next pay check.  So the answer to the question is:

C. After the borrower’s next paycheck.

6 0
1 year ago
Read 2 more answers
Ben swims​ 50,000 yards per week in his practices. Given this amount of​ training, he will swim the​ 100-yard butterfly in 51.5
Elanso [62]

Answer:

MArginal productivity: \frac{dt}{dL}=-0.0002

We can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.

Step-by-step explanation:

The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.

In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.

The marginal productivity can be expressed as:

\frac{dt}{dL}

where dt is the variation in time and dL is the variation in training yards.

We can not derive the function because it is not defined, but we can approximate with the last two points given:

\frac{dt}{dL}\approx\frac{\Delta t}{\Delta L} =\frac{t_2-t_1}{L_2-L_1}=\frac{44.6-46.4}{70,000-60,000}=\frac{-2.0}{10,000}=-0.0002

Then we can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.

This is an approximation that is valid in the interval of 60,000 to  70,000 yards of training.

6 0
1 year ago
The ratio of the areas of two similar parallelogram is 4:9. Find the height of the bigger one if the smaller is if height 4cm
N76 [4]

Answer:

look it up because found the correct answer there

Step-by-step explanation:

4 0
2 years ago
What is the greatest integer value of y for which 5y - 20 &lt; 0?
Anna [14]
5y - 20 < 0...add 20 to both sides
5y < 20...divide both sides by 5
y < 20/5
y < 4 (this states that y is less then 4)

Therefore, the greatest integer that y could be is 3 (because integers cannot be fractions, they have to be whole numbers)
6 0
1 year ago
Read 2 more answers
Suppose that Kevin can choose to get home from work by car or bus. When he chooses to get home by car, he arrives home after 7 p
astraxan [27]

Answer:

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = 0.838

Step-by-step explanation:

Let the probability that Kevin arrives home after 7 pm be P(L)

Probability that Kevin uses the bus = P(B)

Probability that Kevin uses the car = P(C)

Probability of arriving home after 7 pm if the car was taken = P(L|C) = 4% = 0.04

Probability of arriving home after 7 pm if the bus was taken = P(L|B) = 15% = 0.15

The bus is cheaper, So, he uses the bus 58% of the time.

P(B) = 58% = 0.58

P(C) = P(B') = 1 - P(B) = 1 - 0.58 = 0.42

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = P(B|L)

The conditional probability P(A|B) is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

Hence, the required probability, P(B|L) is given as

P(B|L) = P(B n L) ÷ P(L)

But we do not have any of P(B n L) and P(L)

Although, we can obtain these probabilities from the already given probabilities

P(L|C) = 0.04

P(L|B) = 0.15

P(B) = 0.58

P(C) = 0.42

P(L|C) = P(L n C) ÷ P(C)

P(L n C) = P(L|C) × P(C) = 0.04 × 0.42 = 0.0168

P(L|B) = P(L n B) ÷ P(B)

P(L n B) = P(L|B) × P(B) = 0.15 × 0.58 = 0.087

P(L) = P(L n C) + P(L n B) = 0.0168 + 0.087 = 0.1038 (Since the bus and the car are the two only options)

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm

= P(B|L) = P(B n L) ÷ P(L)

P(B n L) = P(L n B) = 0.087

P(L) = 0.1038

P(B|L) = (0.087/0.1038) = 0.838150289 = 0.838

Hope this Helps!!!

8 0
2 years ago
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