Twelve of the 20 students in Mr. Skinner’s class brought lunch from home. Fourteen of the 21 students in Ms. Cho’s class brought
2 answers:
Solution:
Number of students in Mr.Skinner's class who brought lunch from home if there are 20 students in the class=12
Fraction of students who brought lunch from home in Mr. Skinner's class=
Number of students in Ms. Cho's class who brought lunch from home if there are 21 students in the class=14
Fraction of students who brought lunch from home in Ms. Cho's class=
As Siloni is using two 15-section spinners to simulate randomly selecting students from each class and predicting whether they brought lunch from home or will buy lunch in the cafeteria.
Number of Congruent sectors in each Spinner=15
So, if we represent students from Mr. Skinner's class who brought lunch from home in Spinner having 15 congruent Sectors =
So, if we represent students from Mrs. Cho's class who brought lunch from home in Spinner having 15 congruent Sectors =
Mr Skinner class +1 = Mr's Cho's Class
So Ms Cho's class =One more sector of the Skinner-class spinner will represent bringing lunch from home.
Option A which is One more sector of the Skinner-class spinner will represent bringing lunch from home represents Ms Cho's Class.
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Answer:
There is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 300
p = 5% = 0.05
Alpha, α = 0.05
Number of dead pixels , x = 24
First, we design the null and the alternate hypothesis
This is a one-tailed(right) test.
Formula:
Putting the values, we get,
Now, we calculate the p-value from excel.
P-value = 0.00856
Since the p-value is smaller than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Conclusion:
Thus, there is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.