Answer:
The volume of the larger solid is 
Step-by-step explanation:
step 1
Find the scale factor
we know that
If two figures are similar , then the ratio of its surface areas is equal to the scale factor squared
so
Let
z-------> the scale factor
x-------------> surface area larger solid
y-------------> surface area smaller solid
substitute
----> scale factor
step 2
Find the volume of the larger solid
we know that
If two figures are similar , then the ratio of its volumes is equal to the scale factor elevated to the cube
so
Let
z-------> the scale factor
x-------------> volume of the larger solid
y-------------> volume of the smaller solid
we have
substitute the values
Answer:
11 inches by 11 inches
Step-by-step explanation:
The dimensions of the original photo were 11 inches by 11 inches.
We are informed that the area of the reduced photo is 64 square inches and that In the equation (x – 3)^2 = 64, x represents the side measure of the original photo.
In order to solve for x, we shall first take square roots on both sides of the equation;
The square root of (x – 3)^2 is simply (x - 3).
The square root of 64 is ±8 but we ignore -8 since the dimensions of any figure must be positive.
Therefore, we have the following equation;
x - 3 = 8
x = 8 + 3
x = 11
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y. If the equation is written in the slope-intercept form, plug in the slope and the x and y coordinates for a point on the line to solve y. Hope this helped! :)
Answer:
Step-by-step explanation:
v = {[(20sin36°)i + (20cos36°)j] + 10i} mi/h
vE = 20sin36º + 10 = 21.76 mi/h
vN = 20cos36° = 16.18 mi/h
v = √(vE2 + vN2) = √(21.762 + 16.182) mi/h = 27.12 mi/h
θ = tan-1(vN/vE) = tan-1(16.18/21.76) = 36.6º north of east
Answer:
In Right Δ ABC with right angle B,
∠A=(3 x -8)°, ∠B=90°, ∠C=(x-2)°
∠A+∠B+∠C=180°[∠ sum property of triangle]
3 x-8+90 + x-2=180
Adding and subtracting like terms
4 x-10+90=180
4 x+80=180
4 x=180-80
4 x=100
x=100/4
x=25°
∠A=3×25-8=75-8=67°
