Answer:
Due to the higher z-score, David has the higher standardized score
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Which student has the higher standardized score
Whoever had the higher z-score.
David:
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So 



Steven:
Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So 



Due to the higher z-score, David has the higher standardized score
Answer:
29.15 km
Step-by-step explanation:
Given;
George walks; 25km west and then 15 km south
Resolving the directions to x and y axis;
North and South represent positive and negative y axis.
East and West represent positive and negative x axis respectively.
25km west
Rx = -25 km
15 km south
Ry = -15 km
The resultant displacement from the house is;
R = √(Rx^2 + Ry^2)
Substituting the values;
R = √((-15)^2 + (-25)^2)
R = √(225+625)
R = √(850)
R = 29.15 km
Therefore, he is 29.15 km from house
Answer:
The answer is C
Step-by-step explanation: Hope this helps!
Answer:
y = x + 1 y = -x + 21
(0, 1) (0, 21)
(1, 2) (1, 20)
(2, 3) (2, 19)
(3, 4) (3, 18)
Step-by-step explanation:
I’m not exactly sure, but I think you have to find the percentage of the people in the math tutoring compared to the total. You can do this by finding the total number of people, which would be 200, and then dividing 40 by 200, to get 20%, so 20% of the total students participated in the math tutoring. So, using this logic, 20% of 100 is 20, so 20 students would go to math tutoring if there was a total of 100 students