Answer:
c. modus ponens
Explanation:
In propositional logic, we learn that <em>modus ponens</em> is a valid argument and a rule of inference. <em>Modus ponens</em> states that "P implies Q, and if P is true, then Q must be true."
Based on these propositions, we learn that all food that is healthy does not taste good, and tofu is healthy. Therefore,
<em>If all food that is healthy does not taste good,</em>
<em>and tofu is healthy to eat,</em>
<em>then tofu does not taste good.</em>
Answer:
Step-by-step explanation:
The function 
has a horizontal asymptote which is 
The function 
has a horizontal asymptote which is 
The function has no horizontal asymptote because the numerator has a degree which is higher than the degree of the denominator,
The function 
has a horizontal asymptote which is 
<h3>
Answer: D. g(x) = f(x)+4</h3>
The graph shows f(x) to have a y intercept at -1, which is where the diagonal line crosses the y axis. We want the y intercept to move to 3. So we must add 4 to the old y intercept to get the new y intercept.
We do this with every single point on f(x) to get g(x) = f(x)+4. This shifts the graph up 4 units.
Answer:
number of shells zoe gives to dev = 7
number of shells zoe is left with = 55-7= 48
number of shells dev has = 9+7=16
Step-by-step explanation:
let the initial number of shells that dev has be A, and initial number of shells that zoe has be B.
let the number of shells that zoe gives to dev be x.
after giiving x shells zoe is left with 3 times the number of shell as that of dev.
therefore number of shells with zoe = 3×number of shells with dev.
number of shells with zoe = initial shells - x = 55-x
number of shells with dev = initial shells + number of shells he gets
= 9+x
therefore (55-x)=3×(9+x)
55-x = 27+3x
55-27=3x+x
4x = 28
x= 7
therefore number of shells zoe gives to dev = 7
number of shells zoe is left with = 55-7= 48
number of shells dev has = 9+7=16
