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mario62 [17]
2 years ago
10

James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposit $500 into the acc

ount each month. How much will be in the account after 20 years? A. $159,744.59 B. $48,407.45 C. $330,600.15 D. $580,894.18
Mathematics
1 answer:
katovenus [111]2 years ago
7 0

Answer:

<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>

Step-by-step explanation:

Annual interest rate is 2.75%. Hence, the monthly interest rate is \frac{2.75}{12}

The amount will be compounded (20\times12) = 240 times.

Every month they deposits $500.

In the first month that deposited $500 will be compounded 240 times.

It will be 500\times [1 + \frac{2.75}{1200} ]^{240}

In the second month $500 will be deposited again, this time it will be compounded 239 times.

It will give 500\times [1 + \frac{2.75}{1200} ]^{239}

Hence, the total after 20 years will be 500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741

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Doug purchased land for $8,000 in 1995. The year value of the land depreciated by 4% each year thereafter. Use an exponential fu
Marta_Voda [28]

Answer:

Option C. $6,012

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to

V=P(1-r)^{t}

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P is the original value  

r is the rate of depreciation  in decimal

t is Number of Time Periods  

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Hope this helps :)

4 0
2 years ago
EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi
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If there is such a scalar function <em>f</em>, then

\dfrac{\partial f}{\partial x}=4y^2

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}

\dfrac{\partial f}{\partial z}=16ye^{4z}

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f(x,y,z)=4xy^2+g(y,z)

Differentiate both sides with respect to <em>y</em> :

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}

\implies\dfrac{\partial g}{\partial y}=4e^{4z}

Integrate both sides with respect to <em>y</em> :

g(y,z)=4ye^{4z}+h(z)

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

f(x,y,z)=4xy^2+4ye^{4z}+h(z)

\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}

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Integrate both sides with respect to <em>z</em> :

h(z)=C

So we end up with

\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}

7 0
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