First you convert the percentage into a decimal. 18% to 0.18, then you multiply that decimal to the price of the item being discounted and bam, you have your price.
Answer: u= ( 4342.08, 5145.92).
Step-by-step explanation: the population mean is estimated using the sample by the formulae assuming a 95% confidence level
u = x' + Zα/2 * (√σ/n) or x' - Zα/2 * (√σ/n)
u = estimated population mean
x' = sample mean = 4744
n = sample size =8
σ = sample standard deviation. = 580
α = level of significance = 1- confidence level = 1-0.95= 0.05
Zα/2 = z score from the normal distribution table for a 2 tailed test = 1.96
First boundary value for interval
u = 4744 + 1.96 ( 580/√8)
u = 4744 + 1.96 * (205.0609)
u = 4744 + 401.92
u = 5145.92
Second boundary value for interval
u = 4744 - 1.96 ( 580/√8)
u = 4744 - 1.96 * (205.0609)
u = 4744 - 401.92
u = 4342.08
Thus the confidence interval for population mean is
u= ( 4342.08, 5145.92).
4x + 14 = k
Do the opposite of PEMDAS
Isolate the x, subtract 14 from both sides
4x + 14 (-14) = k (-14)
4x = k - 14
divide 4 from both sides
4x/4 = (k-14)/4
x = (k-14)/4 is your answer
hope this helps
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution
Answer:

Step-by-step explanation:
We need to find the equation of parabola using given information
- Vertex: (0,0)
- Open to the left
- Focal width = 12
If parabola open left and passes through origin then equation is

Focal width = 12
Focal width passes through focus and focus is mid point of focal width.
Focus of above parabola would be (-a,0)
Passing point on parabola (-a,6) and (-a,-6)
Now we put passing point into equation and solve for a


a can't be negative.
Therefore, a=3
Focus: (-3,0)
Equation of parabola:

Please see the attachment of parabola.
