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mario62 [17]
2 years ago
10

James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposit $500 into the acc

ount each month. How much will be in the account after 20 years? A. $159,744.59 B. $48,407.45 C. $330,600.15 D. $580,894.18
Mathematics
1 answer:
katovenus [111]2 years ago
7 0

Answer:

<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>

Step-by-step explanation:

Annual interest rate is 2.75%. Hence, the monthly interest rate is \frac{2.75}{12}

The amount will be compounded (20\times12) = 240 times.

Every month they deposits $500.

In the first month that deposited $500 will be compounded 240 times.

It will be 500\times [1 + \frac{2.75}{1200} ]^{240}

In the second month $500 will be deposited again, this time it will be compounded 239 times.

It will give 500\times [1 + \frac{2.75}{1200} ]^{239}

Hence, the total after 20 years will be 500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741

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2 years ago
In a random sample of 8 people with advanced degrees in biology, the mean monthly income was $4744 and the standard deviation wa
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Answer: u= ( 4342.08, 5145.92).

Step-by-step explanation: the population mean is estimated using the sample by the formulae assuming a 95% confidence level

u = x' + Zα/2 * (√σ/n) or x' - Zα/2 * (√σ/n)

u = estimated population mean

x' = sample mean = 4744

n = sample size =8

σ = sample standard deviation. = 580

α = level of significance = 1- confidence level = 1-0.95= 0.05

Zα/2 = z score from the normal distribution table for a 2 tailed test = 1.96

First boundary value for interval

u = 4744 + 1.96 ( 580/√8)

u = 4744 + 1.96 * (205.0609)

u = 4744 + 401.92

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Second boundary value for interval

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u = 4744 - 1.96 * (205.0609)

u = 4744 - 401.92

u = 4342.08

Thus the confidence interval for population mean is

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3 0
2 years ago
Solve 5x + 14 = k for x. A. B. x = k – 14 C. x = 5k – 14 D.
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4x + 14 = k

Do the opposite of PEMDAS
Isolate the x, subtract 14 from both sides
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2 years ago
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Answer:

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Given that y1 = e^(4x) is a solution to the differential equation

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Because y2 is a solution to the differential equation, it satisfies

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y2 = ue^(4x)

y2' = u'e^(4x) + 4ue^(4x)

y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)

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Using these,

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