Ask question

Ask question

All categories

1 year ago

8

Peter buys tickets for his family to see his favorite movie, Elephant Mistake. He pays $37.50 for 2 adult tickets and 2 student

tickets. The next week he goes back with his friends and pays $35.25 for 1 adult ticket and 3 student tickets. Choose the system of equations that can be solved to find the price of an adult ticket, x, and the price of a student ticket, y.

1 answer:

WARRIOR [948]1 year ago

8 0

Answer:

the price of adult ticket and student ticket be $10.50 and $8.25 respectively

Step-by-step explanation:

Let us assume the price of adult ticket be x

And, the price of student ticket be y

Now according to the question

2x + 2y = $37.50

x + 3y = $35.25

x = $35.25 - 3y

Put the value of x in the first equation

2($35.25 - 3y) + 2y = $37.50

$70.50 - 6y + 2y = $37.50

-4y = $37.50 - $70.50

-4y = -$33

y = $8.25

Now x = $35.25 - 3($8.25)

= $10.5

Hence, the price of adult ticket and student ticket be $10.50 and $8.25 respectively

You might be interested in

Nandini makes 'halwa' one evening and divides it into four equal portions for her family of four. However, just as they are abou

wel

Answer:

5%

Step-by-step explanation:

Total 'halwa' made = 1

Divided into four equal portion = 1/4

Arrival of an unexpected guest = 1/5

By what percentage has each family member's share been reduced:

Change in the sharing proportion:

Previous share ratio - new sharing ratio

(1/4 - 1/5) = (5 - 4) / 20 = 1/20

That means total reduction in the sharing = 1/ 20

Since each member comes contributed equally:

Reduction in each family member's share ;

(1 / 20) ÷ 4

(1 / 20) * 1/4 = 1/ 80

Percentage reduction:

(Reduction / original share) * 100%

[(1/80) ÷ (1/4)] * 100

(1/80 * 4/1) * 100%

(1/20) * 100%

= 5%

Reduction in each family members share = 5%

3 0

1 year ago

Select all the points that are on the line through (0,5) and (2,8)

OverLord2011 [107]

Answer:

HI B , E

Step-by-step explanation:

I NEED CREADIT

5 0

1 year ago

Solve the recurrence relation: hn = 5hn−1 − 6hn−2 − 4hn−3 + 8hn−4 with initial values h0 = 0, h1 = 1, h2 = 1, and h3 = 2 using (

musickatia [10]

(a) Suppose $h_n=r^n$ is a solution for this recurrence, with $r\neq0$ . Then

$r^n=5r^{n-1}-6r^{n-2}-4r^{n-3}+8r^{n-4}$
$\implies1=\dfrac5r-\dfrac6{r^2}-\dfrac4{r^3}+\dfrac8{r^4}$
$\implies r^4-5r^3+6r^2+4r-8=0$
$\implies (r-2)^3(r+1)=0\implies r=2,r=-1$

So we expect a general solution of the form

$h_n=c_1(-1)^n+(c_2+c_3n+c_4n^2)2^n$

With $h_0=0,h_1=1,h_2=1,h_3=2$ , we get four equations in four unknowns:

$\begin{cases}c_1+c_2=0\\-c_1+2c_2+2c_3+2c_4=1\\c_1+4c_2+8c_3+16c_4=1\\-c_1+8c_2+24c_3+72c_4=2\end{cases}\implies c_1=-\dfrac8{27},c_2=\dfrac8{27},c_3=\dfrac7{72},c_4=-\dfrac1{24}$

So the particular solution to the recurrence is

$h_n=-\dfrac8{27}(-1)^n+\left(\dfrac8{27}+\dfrac{7n}{72}-\dfrac{n^2}{24}\right)2^n$

(b) Let $G(x)=\displaystyle\sum_{n\ge0}h_nx^n$ be the generating function for $h_n$ . Multiply both sides of the recurrence by $x^n$ and sum over all $n\ge4$ .

$\displaystyle\sum_{n\ge4}h_nx^n=5\sum_{n\ge4}h_{n-1}x^n-6\sum_{n\ge4}h_{n-2}x^n-4\sum_{n\ge4}h_{n-3}x^n+8\sum_{n\ge4}h_{n-4}x^n$
$\displaystyle\sum_{n\ge4}h_nx^n=5x\sum_{n\ge3}h_nx^n-6x^2\sum_{n\ge2}h_nx^n-4x^3\sum_{n\ge1}h_nx^n+8x^4\sum_{n\ge0}h_nx^n$
$G(x)-h_0-h_1x-h_2x^2-h_3x^3=5x(G(x)-h_0-h_1x-h_2x^2)-6x^2(G(x)-h_0-h_1x)-4x^3(G(x)-h_0)+8x^4G(x)$
$G(x)-x-x^2-2x^3=5x(G(x)-x-x^2)-6x^2(G(x)-x)-4x^3G(x)+8x^4G(x)$
$(1-5x+6x^2+4x^3-8x^4)G(x)=x-4x^2+3x^3$
$G(x)=\dfrac{x-4x^2+3x^3}{1-5x+6x^2+4x^3-8x^4}$
$G(x)=\dfrac{17}{108}\dfrac1{1-2x}+\dfrac29\dfrac1{(1-2x)^2}-\dfrac1{12}\dfrac1{(1-2x)^3}-\dfrac8{27}\dfrac1{1+x}$

From here you would write each term as a power series (easy enough, since they're all geometric or derived from a geometric series), combine the series into one, and the solution to the recurrence will be the coefficient of $x^n$ , ideally matching the solution found in part (a).

3 0

1 year ago

David is making rice for his guests based on a recipe that requires rice, water, and a special blend of spice, where the rice-to

steposvetlana [31]

Answer:

8 servings

Step-by-step explanation:

At the ratio of 15:1, the 75 grams of rice in one serving will require 75/15 = 5 g of spice. David's inventory of 40 g of spice is enough for ...

40 g/(5 g/serving) = 8 servings

7 0

2 years ago

Read 2 more answers

A square OABC with the length of a side 6 cm and circle k(O) with a radius 5 cm are given. Which of the lines OA , AB , BC , or

Pavel [41]

Answer:

AC and OA

Step-by-step explanation:

-A secant is a line connecting two points on the circle.

-Given the square OABC of sides 6cm and a circle of r=5cm and the center of the circle as O, and that the radius of the circle is less than the side of the square:

-The circle passes through OA and OC, but doesn't pass through AB and BC.

Hence, AC and OA are the circle's secants.

5 0

1 year ago