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velikii [3]
2 years ago
5

The formula h -15 = 3.2t gives the height h in inches of a plant t weeks after planting.

Mathematics
2 answers:
Anon25 [30]2 years ago
8 0

Answer:

15 Inch

Step-by-step explanation:

The formula is

h-15=3.2t\\

To find initial height, put t = 0.

h-15=3.2\times 0\\h-15=0\\h=0+15 \\h=15

Hence, initial height of the plant = 15 inch

Maurinko [17]2 years ago
5 0
Substitute t = 0, to get the initial height
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Find the absolute maximum and absolute minimum of the function f(x,y)=2x2−4x+y2−4y+1 on the closed triangular plate bounded by t
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First check for the critical points of <em>f</em> by checking where the first-order derivatives vanish.

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Now check on the boundary lines themselves. If <em>x</em> = 0, then

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which has a maximum value of -3 when <em>y</em> = 2 (so we get the same critical point as before).

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A study was made of seat belt use among children who were involved in car crashes that caused them to be hospitalized. It was fo
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Answer:

a) P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

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And using the complement rule we got:

P(Z>-1.096) =1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(7.37,1.25)  

Where \mu=7.37 and \sigma=1.25

We are interested on this probability

P(5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

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Part b

For this case we want this probability:

P(X>6)

And we can use the z score and we got:

P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)

And using the complement rule we got:

P(Z>-1.096) =1-P(Z

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