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2 years ago

Plz help ASAP, tysm! Plz show ur work!

Mathematics

2 answers:

insens350 [35]2 years ago

7 0

Answer:

Step-by-step explanation:

Given 3x - 2y = 0, which can be re-written as 3x = 2y, find the intercepts.

y-intercept: let x = 0 and find y. y = 0. So the y-intercept is (0, 0).

x-intercept: let y = 0 and find x. The x-intercept is (0, 0) also.

Read more on Brainly.com - brainly.com/question/12681291#readmore

anygoal [31]2 years ago

4 0

Answer:

Step-by-step explanation:

Given 3x - 2y = 0, which can be re-written as 3x = 2y, find the intercepts.

y-intercept: let x = 0 and find y. y = 0. So the y-intercept is (0, 0).

x-intercept: let y = 0 and find x. The x-intercept is (0, 0) also.

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Which expressions represent rational numbers? Select all the apply.

geniusboy [140]

Answer:

1. sqrt 100 x sqrt 100

2. 13/5 + sqrt 81

3. sqrt 9 + sqrt 729

4. Not a rational number

5. Not a rational number

6. 3/5 + 2.5

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2 years ago

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Which steps can be used to solve StartFraction 6 Over 7 EndFraction x + one-half = StartFraction 7 Over 8 EndFraction for x? Che

34kurt

Answer:

Subtract One-half from both sides of the equation.

Divide both sides by 6/7

Multiply both sides by 7/6

Step-by-step explanation:

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2 years ago

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If the size of the sample to be used in a particular test of attributes has not been determined by utilizing statistical concept

EleoNora [17]

Answer:

C) The auditor may or may not achieve the desired risk of assessing control risk too low.

Step-by-step explanation:

In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.

This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean

5 0

2 years ago

ANSWER ALL 5 PARTS.

N76 [4]

A function $f$ from a set A to a set B is defined as a relation that assings to each element $x$ in the set A exactly one element $y$ in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is $x$ feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let $x$ be the width of the tomato patch, then the function that matches this statement is:

$\boxed{Wa(x)=\frac{x}{2}}$

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

 $\boxed{La(x)=x+2}$

2. Area of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then the area of a rectangle is the product of the length and width. So:

 $A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}$

3. Combined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

 $Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}$

4. Write the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:

 $Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x$

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

 $31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06$

Therefore the area of the remaining space is:

 $\boxed{Aa(7.06)=7.06ft^{2}}$

6 0

2 years ago

Rationalize the denominator of $\frac{2}{3\sqrt{5} + 2\sqrt{11}}$ and write your answer in the form $\displaystyle \frac{A\sqrt{

vlada-n [284]

Answer:

Step-by-step explanation:

Given the surdic expression $\frac{2}{3\sqrt{5} + 2\sqrt{11}}\\$ , to rationalize the expression, we will have to multiply the numerator and denominator of the expression by the conjugate of the denominator as shown;

$= \frac{2}{3\sqrt{5} + 2\sqrt{11}} * \frac{3\sqrt{5} - 2\sqrt{11}}{3\sqrt{5} - 2\sqrt{11}}\\\\= \frac{2(3\sqrt{5} - 2\sqrt{11})}{(3\sqrt{5} + 2\sqrt{11})(3\sqrt{5} - 2\sqrt{11})}\\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{9\sqrt{25}+6\sqrt{55}- 6\sqrt{55}-4\sqrt{121} } \\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{9(5)-4(11) }\\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{45-44 }\\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{1}$

Comparing the result $\frac{6\sqrt{5} - 4\sqrt{11} }{1}$ with the expression $\frac{A\sqrt{B} + C\sqrt{D}}{E}$ , it can be seen that A = 6, B = 5, C = -4, D = 11 and E = 1

A+B+C+D+E = 6+5+(-4)+11+1

A+B+C+D+E = 11-4+12

A+B+C+D+E = 19

Hence the value of A+B+C+D+E is 19

4 0

2 years ago