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2 years ago

Write all of the complex numbers that are graphed in the complex plane shown.

Mathematics

2 answers:

Tems11 [23]2 years ago

7 0

A is -3x and 3y

B is -1x and -1y

C is 3x and -4y

D is 4x and 1y

Ket [755]2 years ago

3 0

The y-axis can be considered the imaginary axis.

The x-axis is the real axis.

So we can conclude that:

A: (-2, 3i)

B: (-1, -i)

C: (3, -4i)

D: (4, i)

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It takes 313131 employees and \$7500$7500dollar sign, 7500 to build a car, and it takes 191919 employees and \$4300$4300dollar s

Liula [17]

Answer:

a) 31c + 19m ≤ 706

b) 7500c + 4300m > 84000

Step-by-step explanation:

To build a car, we need 31 employees and $7500.

To build a motorcycle, we need 19 employees and $4300.

Let C denote the number of cars they build.

Let M denote the number of motorbikes they build.

Recall that ;

To build a career, we need 31 employees. To build "c" cars, we will need 31*c = 31c employees

To build a motorcycle, we need 19 employees. To build "m" motorcycle, we will need 19*m = 19m

Since the maximum number of employees used to build the car and motorcycle is at most 706, we have

31c + 19m ≤ 706

It takes $7500 to build car. To build "c" cars, we need 7500*c = $7500c

It also takes $4300 to build "m" motorcycles. We need 4300*m = $4300m

Since Genghis motors wont to spend more than $84000 on both cars and motorcycles, we have

7500c + 4300m > 84000

For the condition based on the number of employees, we have

31c + 19m ≤ 706

For the condition based on the number of dollars, we have

7500c + 4300m > 84000

3 0

2 years ago

What is three decimals that have a sum of 10.806

White raven [17]

Answer:

10 + 0.8 + 0.006 = 10.806

Step-by-step explanation:

Pick any two decimal numbers. The third one will be the difference between 10.806 and the sum of the two numbers you picked.

For example, choose 938.2 and 3.0055. Their sum is 941.2055. Then the third number that will make the sum be 10.806 is ...

10.806 -941.2055 = -930.3995

So, your three numbers could be ...

{938.2, 3.0055, -930.3995}

7 0

2 years ago

Hannah has 127 books in her collection. Her school is hosting a book donation. There are z students at her school, and they each

luda_lava [24]

$127 \div z$

8 0

2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

The probability, $P =0.0002$

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago

a scientist wants to study 24 stars he studies 1/3 of them one week and 1/4 of them next week how many of them are left to study

zvonat [6]

6 because 1/3 of 24 is 8 and 1/4 of 8 is 6

4 0

2 years ago