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sergeinik [125]
2 years ago
11

The bottom of Ignacio's desktop is 74.5\,\text{cm}74.5cm74, point, 5, space, c, m from the floor. Ignacio sits in his adjustable

chair, and the tops of his legs are 49.3\,\text{cm}49.3cm49, point, 3, space, c, m from the floor. Each clockwise rotation of the knob on the chair raises Ignacio's legs by 4.8\,\text{cm}4.8cm4, point, 8, space, c, m.
Write an inequality to determine the number of clockwise rotations, rrr, Ignacio could make with the knob without his legs touching the desk.
Mathematics
1 answer:
Musya8 [376]2 years ago
7 0

Answer:

The inequality is:

49.3+4.8r <74.5

The solution set is r < 5.25

Step-by-step explanation:

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This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.
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Read 2 more answers
2. A statistics student plans to use a TI-84 Plus calculator on her final exam. From past experience, she estimates that there i
Anarel [89]

Answer:

  1. P(≥1 working) = 0.9936
  2. She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.

Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936

2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.

If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.

This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

_____

My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)

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2 years ago
Bella is working on the world record for longest beaded necklace. She has 10,000 glass beads that have a diameter of 0.4 cm. If
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Answer:

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A sample of tritium-3 decayed to 94.5% of its original amount after a year.
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(a) If y(t) is the mass after t days and y(0) = A then y(t) = Ae^{kt}.

y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945

\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\  ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\&#10;t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}

(b)
Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\&#10;t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}
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2 years ago
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