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krok68 [10]
2 years ago
14

ΔABC is similar to ΔAXY by a ratio of 4:3. If BC = 24, what is the length of XY?

Mathematics
2 answers:
pogonyaev2 years ago
6 0

Answer:

18

Step-by-step explanation:

24/4 = 6 so....

4*6 is 24 and 3*6 is 18

faltersainse [42]2 years ago
3 0

Answer:

Length of XY is 18 units.

Step-by-step explanation:

Given,

\triangle ABC\sim \triangle AXY

By the ratio of 4 : 3

That is, the ratio of corresponding sides of triangles ABC and AXY is 4 : 3,

\implies \frac{AB}{AX}=\frac{BC}{XY}=\frac{AC}{AY}=\frac{4}{3}

We have, BC = 24 units,

\frac{24}{XY}=\frac{4}{3}

72=4XY

\implies XY=\frac{72}{4}=18

Hence, the length of XY is 18 units.

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La hormiguita Fidencia se encontro una hojita, la cargo y se llevo al hormiguero. Le dio a su amiguita 1/5 y ella se comió 1/3 d
vredina [299]

Answer:

The ant Fidencia ate more

Step-by-step explanation:

The question in English

The ant Fidencia found a leaf, the charge and took the anthill. She gave her friend 1/5 and she ate 1/3 of the leaf. Who ate more?

Her friend

Multiply (1/5) by (3/3)

(1/5)*(3/3)=3/15

Ant Fidencia

Multiply (1/3) by (5/5)

(1/3)*(5/5)=5/15

Compare

5/15 > 3/15 -----> two fractions with the same denominator the fraction with the highest numerator is greater

therefore

The ant Fidencia ate more

7 0
2 years ago
A research organization wanted to estimate the average number of hours a college student sleeps per night during the school year
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

Given given that

  • Lower confidence interval = 7.1
  • Upper confidence interval = 7.5
  • As such, We are 95% confident that it's somewhere between 7.1 and 7.5 hours per night

Average value = LCI + UCI /2 = 7.1 + 7.5 / 2

= 7.3hours per night, so we are 95% confident that it's somewhere between 7.1 and 7.5 hours per night which is eventually 7.3hrs per night.

4 0
2 years ago
For making a scatter plot of the data set, which would be the best scale and interval for the axis that represents the amount of
Serga [27]

I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.

Because, you can't just have 1 to 4, as some of the numbers are less than 1.  Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.

For the second question:

I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.

So, the answers are: A) and D).

8 0
2 years ago
the local volleyball team hosts a concession stand to raise money. They can spend $120 to purchase popcorn, candy, and drinks. t
Art [367]
To solve this question, I did an equation:
0.75x + 1.20y = 120
0.75(95) + 1.20(35) = 120
Then multiply:
71.25 + 42 = 120
Now to check:
71.25 + 42 = 113.25
Answer: 120 - 113.25 = $6.75 Hope this helps

7 0
2 years ago
charles deposited $12,000 in the bank. He withdrew $5,000 from his account after one year. If he recives a total amount of $9,34
Schach [20]

Answer:

The rate of simple interest is 9%

Step-by-step explanation:

* Lets talk about the simple interest

- The simple Interest Equation (Principal + Interest)  is:

  A = P(1 + rt)  , Where

# A = Total amount (principal + interest)

# P = Principal amount

# I = Interest amount

# r = Rate of Interest per year in decimal r = R/100

# R = Rate of Interest per year as a percent R = r * 100

# t = Time period involved in months or years

- The rule of the simple interest is I = Prt

* lets solve the problem

- Charles deposited $12,000

∴ P = $12,000

- He withdrew $5,000 from his account after one year

- He receives a total amount of $9,340 after 3 years

∴ A = $9340 and t = 3

- Lets find the inetrest after 1 year

∵ I = Prt

∵ P = 12000

∵ t = 1

∴ I = 12000(r)(1) = 12000r

- Lets subtract the money that he withdrew

∵ He withdrew $5000

∵ He deposit at first 12000

∴ He has after the withdrew 12000 - 5000 = 7000

- The new P for the next 2 years is 7000

- This amount will take the same rate r for another two years

- The total money is $9340

∵ I = A - P

∵ A = 9340

∵ P = 7000

∴ The amount of interest = 9340 - 7000 = 2340

- The amount of interest after 3 years is 2340

- Lets find the amount of interest in the two years

∴ I = 7000(r × 2) = 14000r

- The amount of interest after the 3 years is the sum of the interest in

  the 1st year and the other 2 years

∴ 2340 = 14000r + 12000r

∴ 2340 = 26000r ⇒ divide both sides bu 2340

∴ r = 2340 ÷ 26000 = 0.09

∵ The rate R in percentage = r × 100

∴ R = 0.09 × 100 = 9%

∴ The rate of simple interest is 9%

8 0
2 years ago
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