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mr Goodwill [35]
2 years ago
9

For making a scatter plot of the data set, which would be the best scale and interval for the axis that represents the amount of

fluoride?
1 to 4 with intervals of 1


2 to 5 with intervals of 0.5


0 to 4 with intervals of 2


0 to 4 with intervals of 0.2

Which statement is true?

This scatter plot has two clusters and one outlier.


This scatter plot has no clusters and one outlier.


This scatter plot has one cluster and no outliers.


This scatter plot has no clusters and no outliers.

Mathematics
1 answer:
Serga [27]2 years ago
8 0

I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.

Because, you can't just have 1 to 4, as some of the numbers are less than 1.  Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.

For the second question:

I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.

So, the answers are: A) and D).

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Round to the nearest hundred thousand <br> 89, 659
victus00 [196]

Answer:

The nearest hundred thousand of the provided number is 100,000.

Step-by-step explanation:

Consider the provided number 89, 659

According to place value.

Hundred Th.   Ten Th.   Thousands   hundreds   Tens   Ones

   100,000       10,000        1000             100           10         1

We need to round it to the nearest hundred thousand.

The provided number can be written as 089,659

The digit at the hundred thousand place is 0.

The rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, then rounding digit rounds up by one number.

Here, the number at the ten thousands place is 8, so to round up the number increase the digit of hundred thousand place by 1.

The digit at the hundred thousand place is 0 so increase it by 1.

Thus, the number can be rounded to the nearest hundred thousand is shown as:

100,000

The nearest hundred thousand of the provided number is 100,000.

8 0
2 years ago
Read 2 more answers
Aditi downloads ten paid apps and sixteen free apps on her tablet. Fourteen of them are game apps, and she paid for five of the
netineya [11]

Answer:

P(paid) =  10/26

P(paid | game) = 5/14

The events “paid” and “game” are not independent

5 0
2 years ago
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For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
We know that the angles of a triangle sum to 180°.  For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180

Combining like terms,
16x+20=180

Subtracting 20 from both sides:
16x=160

Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.

For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180

Combining like terms, 
20x-20=180

Adding 20 to both sides:
20x=200

Dividing both sides by 20:
x=10

This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.

Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
5 0
2 years ago
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Biologists conducted a study to investigate the flying velocity of mosquitoes both before and after feeding. The following scatt
Lesechka [4]

Answer:

It represents a mosquito that flew very fast after feeding relative to all other mosquitoes.

Step-by-step explanation:

The point is unusual because the velocity of the mosquito is substantially greater than all other velocities and is probably an outlier.

4 0
2 years ago
Mapiya writes a series of novels. She earned \$75{,}000$75,000dollar sign, 75, comma, 000 for the first book, and her cumulative
qwelly [4]

Answer:

E(n)=75000 \times 2^n

Complete question:

write a function that gives mapiyas cumulative earnings E(n), in dollars when she has written n sequel's

Step-by-step explanation:

According to the question, she earned $75000 for the first book.

Also,We are  given that her cumulative earnings double with each sequel that she writes.

Assuming she has written n sequel's

Now since we are given that her cumulative earnings double with each sequel

So, her initial earning will be 2^n times

So, her earning will be : 75000 \times 2^n

Now we are given that cumulative earnings is denoted by E(n)

So, the function becomes :E(n)=75000 \times 2^n

Hence a function that gives Mapiya's cumulative earnings E(n), in dollars when she has written n sequel's  is  E(n)=75000 \times 2^n

4 0
2 years ago
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