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2 years ago

The lines below are perpendicular. If the green line has a slope of -1/9, what is

Mathematics

1 answer:

mojhsa [17]2 years ago

6 0

Answer:

Step-by-step explanation:

The slopes are perpendicular lines are opposite reciprocals.

If one line has slope - 1/9, then the perpendicular to it has slope 9/1 or 9.

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Which number has the greatest absolute value? <br> a. 0 <br> b. 10 <br> c. –10 <br> d. –20?

Triss [41]

Keep in mind, absolute values are always positive, even when they say negative.That is because the absolute value of a number is just the distance that number is from 0. Example : -5 and 5...they are both 5 spaces from 0...doesn't matter if it is negative or positive, it is still 5 spaces.

|0| = 0
|10| = 10
|-10| = 10
|-20| = 20

so ur answer is : | -20 |

6 0

2 years ago

Carmen draws this area model to help her divide 1,800 by 9. She says the quotient is 20

lisov135 [29]

Answer: the answer is 200

Step-by-step explanation:

6 0

2 years ago

Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at

kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event

- The probability of an Event = Number of favorable outcomes ÷ Total

number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0

2 years ago

Read 2 more answers

The Acme Candy Company claims that 60% of the jawbreakers it produces weigh more than 0.4 ounces. Suppose that 800 jawbreakers

vichka [17]

Answer:

Yes, it would be statistically significant

Step-by-step explanation:

The information given are;

The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%

Number of jawbreakers in the sample, n = 800

The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = $\mu _ {\hat p}$ =p

The formula for the standard deviation of a proportion is $\sigma _{\hat p} =\sqrt{\dfrac{p(1-p)}{n} }$

Solving for the standard deviation gives;

$\sigma _{\hat p} =\sqrt{\dfrac{0.6 \cdot (1-0.6)}{800} } = 0.0173$

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480

For statistical significance the difference from the mean = 2× $\sigma _{\hat p}$ = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7

The z-score of 494 jawbreakers is given as follows;

$Z=\dfrac{x-\mu _{\hat p} }{\sigma _{\hat p} }$

$Z=\dfrac{494-480 }{0.0173 } = 230.94$

Therefore, the z-score more than 2 × $\sigma _{\hat p}$ which is significant.

8 0

2 years ago

a barangay has 1000 individuals and its population doubles every 60 years. Give an exponential model for the barangay's populati

sdas [7]

Answer:

P(t) = 1000e^(0.01155)t

Step-by-step explanation:

Let the population of barangay be expressed according to the exponential formula;

P(t) = P0e^kt

P(t) is the population of the country after t years

P0 is the initial population

t is the time

If barangay has 1000 initially, this means that P0 = 1000

If the population doubles after 60years then;

at t = 60, P(t) = 2P0

Substitute into the formula

2P0 = P0e^k(60)

2 = e^60k

Apply ln to both sides

ln2 = lne^60k

ln2 = 60k

k = ln2/60

k = 0.01155

Substitute k = 0.01155 and P0 into the expression

P(t) = 1000e^(0.01155)t

Hence an exponential model for barangay's population is

P(t) = 1000e^(0.01155)t

7 0

2 years ago