Answer:
The distance of flag post from Y is 38.13 m
Step-by-step explanation:
Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.
Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.
Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.
Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,



Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,



Refer attachment 1.
From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.
∠YFX+∠FYX+∠FXY=180°
∠YFX+50°+72°=180°
∠YFX=58°
Refer attachment 2.
Now the distance FY can be calculated using sin rule as follows,

Substituting the values,

Simplifying first two terms,
Cross multiplying,


m
First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
The width is half the length, so is
width = (1/2)*length
width = (1/2)*(<span>3.2a + 0.18b) cm
width = (1.6a +0.09b) cm
The perimeter of the rectangle is twice the sum of length and width.
perimeter = 2*(length + width)
perimeter = 2*((3.2a +0.18b) cm + (1.6a +0.09b) cm)
perimeter = 2*(4.8a +0.27b) cm)
perimeter = (9.6a +0.54b) cm
Sasha did not get this answer, so apparently ...
her reasoning was not correct.</span>
Try this option (see the attachment), if it is possible check result in other sources.
Given:
Cost of four lines = $125
Cost of each additional line = $15
Jason wants to spend at most $200 per month on cell phone expenses.
To find:
The inequality for the given situation.
Solution:
Let
be the number of additional line.
Cost of one additional line = $15
Cost of
additional line = 
Total cost = Fixed cost + Addition cost
= 
It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

Therefore, the correct option is C.