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Marianna [84]
1 year ago
15

A coordinate plane showing Running. The x-axis shows seconds, the y-axis shows feet. One solid line showing Moises starting at (

0, 0) and passing through the points at (1, 5) and (3, 15). One dashed line showing Xavier, starting at (0, 0), and passing through the points at (2, 15) and (4, 30). The distance, in feet, two boys travel per second on a treadmill is shown to the left. Which comparison is accurate? Xavier is traveling at 1.5 feet per second. Moises is going faster than Xavier. The difference in their rates of change is 1 foot per second. If both boys remain on the treadmill for 10 minutes, Xavier will have traveled a greater distance
Mathematics
1 answer:
torisob [31]1 year ago
7 0

Answer:

Step-by-step explanation:

s

Guest
1 year ago
BUM
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The area of a square is stored in a double variable named area. write an expression whose value is length of the diagonal of the
lbvjy [14]

First of all, a bit of theory: since the area of a square is given by

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s = \sqrt{A}.

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Kelly asked some of her classmates how many hours of sleep they get on school nights. Here are the results:
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A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

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Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

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h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

V= 1,277.63\pi\ ft^{3}

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

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6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

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8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

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1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

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Answer:

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