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DerKrebs [107]
2 years ago
10

Decide whether the function is an exponential growth or exponential decay function, and find the constant percentage rate of gro

wth or decay.
f(x) = 2479 ⋅ 0.9948x
Mathematics
1 answer:
frosja888 [35]2 years ago
8 0
Consider the function f ( x ) = 2479 ⋅ 0.9948x First compare this with f ( x ) po ( 1 + r ) ^ 2 We get po = 2479 And 1 + r = 0.9948 = 1 – 0.0052 r = -0.0052 < 0 Therefore, f is an exponential decay function with a decay rate of 0.0052 x 100 = 0.52% 
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Solve the equation or inequality 3/2t-16=4/3t-6
Tamiku [17]

Answer:

<em>t=60</em>

Step-by-step explanation:

3/2t-16=4/3t-6

(subtract 4/3t from both sides)

3/2t-16-4/3t=-6

(add 16 to both sides)

3/2t-4/3t=-6+16

(simplify)

1/6t=10

(divide by 1/6 (or multiply by 6 on both sides)

t=60

7 0
2 years ago
Express 25.6 nanometres in metres, giving your answer in standard form.​
zhannawk [14.2K]

Answer:

10 to power of -8 so 0.00000001 I think

8 0
2 years ago
K is the midpoint of segment HL . H has coordinates (1, -7 ) , and K has coordinates(-9, 3 ). Find the coordinates of other end
Andrei [34K]

Answer:

Coordinates of other end point L = ( -19, 13 )

Explanation:

 The mid point of the coordinates (a,b) and (c,d) is given by (\frac{a+c}{2},\frac{b+d}{2})

 Here we have (a,b) = (1,-7) and (\frac{a+c}{2},\frac{b+d}{2}) = (-9,3) , we need to find (c,d).

 \frac{a+c}{2} =-9\\ \\ 1+c=-18\\ \\ c=-19\\\\ \frac{b+d}{2} =3\\ \\ -7+d=6\\ \\ d=13

So coordinates of other end point L = ( -19, 13 )

8 0
2 years ago
Read 2 more answers
In the following diagram \overline{DE} \parallel \overline{FG}
Gnesinka [82]

Answer:

<x = 31°

Step-by-step explanation:

m<BCA = m<GCJ (vertical angles)

m<BCA = 59° (substitution)

Since line KL is perpendicular to line FG, the angle formed at point B is 90°.

Therefore, m<ABC = 90°

m<BAC + m<ABC + m<BCA = 180° (sum of triangle)

m<BAC + 90° + 59° = 180° (Substitution)

m<BAC + 149° = 180°

m<BAC = 180° - 149°

m<BAC = 31°

<x = <BAC (vertical angles)

m<x = 31° (substitution)

7 0
2 years ago
Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model
Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

\text{F}_(_n__1-1, n_2-1_)

Here, n_1 = sample of 15 Claiborne models

         n_2 = sample of 12 Klein models

So, the degrees of freedom = (n_1-1, n_2-1) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The test statistics that will be used here is F-test which is given by;

                          T.S. = \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ \text{F}_(_n__1-1, n_2-1_)

where, s_1^{2} = sample variance of the Claiborne models data = \frac{\sum (X_i-\bar X)^{2} }{n_1-1} = 1.007

s_2^{2} = sample variance of the Klein models data = \frac{\sum (X_i-\bar X)^{2} }{n_2-1} = 2.653    

So, the test statistics =  \frac{1.007}{2.653 } \times 1  ~ \text{F}_(_1_4,_1_1_)

                                   = 0.3796

Hence, the value of the test statistic is 0.3796.

3 0
2 years ago
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