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2 years ago

John is selling his pizza for $6 per slice in an area of high demand. However, customers are not buying his pizza.

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

6 0

For starters lower the price

Slav-nsk [51]2 years ago

3 0

Answer:

Since John is selling his pizza for six dollars a slice and people are not buying it; he has an excess in supply. Customers may not be coming to his shop because his prices are too high. So, he should decrease the price of a slice of pizza to bring in more customers. Which would get rid of the excess supply and make the supply and demand equal.

Step-by-step explanation:

edge 2020

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The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

5 0

2 years ago

In the diagram, DG = 12, GF = 4, EH = 9, and HF = 3. Triangle D E F is shown. Line G H is drawn parallel to side D E within the

Komok [63]

Answer:

<DFE is congruent to <GFH

Step-by-step explanation:

you need an angle to prove SAS and <DFE is congruent to <GFH

5 0

2 years ago

Montel collected 26 leaves for his science project. he wants to put 6 leaves on a page. which shows how many pages montel will n

MissTica

You divide 26 by 6, and you get 4 1/3, so I guess Montel will need 5 pages.

6 0

2 years ago

Read 2 more answers

The graph represents the feasible region for the system:

morpeh [17]

We have been given a system of inequalities and an objective function.

The inequalities are given as:

$y\leq 2x\\
x+y\leq 45\\
x\leq 30\\$

And the objective function is given as:

$P=25x+20y$

In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.

The graph of the region is shown below:

From the graph, we can see that corner points of the feasible region are:

(x,y) = (15,30),(30,15) and (30,60).

Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.

$\text{At (15,30)}\Leftrightarrow P=25\cdot 15+20\cdot 30=975\\
\text{At (30,15)}\Leftrightarrow P=25\cdot 30+20\cdot 15=1050\\
\text{At (30,60)}\Leftrightarrow P=25\cdot 30+20\cdot 60=1950\\$

Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30

3 0

2 years ago

Read 2 more answers

If m□ebd=4x-8 and m□ebc=5x+20,find the value of x and m□ebc

RoseWind [281]

m□ebd=4 x-8 and m□ebc=5 x+20

This is solvable only if e b is the initial side and b d and b c lies on opposite side of each other and lies on a line i.e c,b,d are Collinear.

∠ebd and ∠ebc will form a linear pair.The meaning of linear pair is that angles forming on one side of a straight line through a common vertex which are adjacent is 180°.

i.e

∠ ebd + ∠ebc = 180°

4 x- 8 + 5x + 20= 180°

adding like terms

⇒ 9 x +12 =180°

⇒ 9 x = 180° - 12

⇒ 9 x = 168°

⇒ x =( 168/9)°=(56/3)°

now m□ebc =5 x +20

= 5 × 56/3 + 20

= 280/3 + 20

=340/3

m□ebc=( 340/3)°

So, solution set is x =(56/3)° and m□ebc =(340/3)°

5 0

2 years ago