Answer: the total amount that you can earn in 15 years is $737245. Option C
Step-by-step explanation:
You receive an annual salary of $32,900 and each year, you are assured of a 5.5% raise. Assuming there was no raise, you get 100% of your previous salary each year. With a raise of 5.5%, you will get 100 + 5.5 = 105.5% of your previous salary for each year. This is a geometric progression and we want to determine the sum of 15 terms(15 years).
The formula for the sum of terms in a geometric progression is
Sn = [a(r^n - 1)]/ r - 1
Sn = sum of n terms
a = the first term
n = number of terms
r = common ratio
From the information given,
a = 32900
n = 15
r = 105.5/100 = 1.055
S15 = [32900(1.055^15 - 1)] / 1.055 - 1
S15 = [32900(2.23247649 - 1)] / 0.055
S15 = 32900 × 1.23247649) / 0.055
S15 = 737245.0277
S15 = $737245
To solve this problem you must appply the formula for simple interest, which is:
I = RxPxN
I: Simple Interest.
R:Rate (9.5$/100=0.095/12).
P: The principal (P=$9000).
N:number of periods (N=24).
When you substitute these values into the formula, you obtain:
I=RxPxN
I=(0.095/12)x9000x24
I=$1710
Therefore, the monthly payment is:
$1710/24=$71.25
What is Jerry's monthly payment?
The answer is: Jerry's monthly payment is $71.25
PLEASE HELP! In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that triangle RST is congruent to triangle RSQ given that RS ⊥ ST, RS ⊥ SQ, and ∠STR ≅ ∠SQR. Submit the entire proof to your instructor.
Given:
RS ⊥ ST
RS ⊥ SQ
∠STR ≅ ∠SQR
Prove:
△RST ≅ △RSQ
Answer:
x= -1, x=4
Step-by-step explanation:
5x²-15x-20
5x²-20x+5x-20=0
5x(x-4) +5(x-4)
(5x+5) (x-4) =0
5x=-5 or x=4
x= -5/5. or x=4
x= -1 or x=4
By Green's theorem, the integral of 
along 
is
which is 6 times the area of 
, the region with as its boundary.
We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle 
and radius 
, the area 
of the sector is proportional to the circle's overall area according to
so that the value of the integral is
