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1 year ago

BRAINLIESTTTTT ANSWER!!!!!!!!!!!!!!!

Mathematics

1 answer:

Ksenya-84 [330]1 year ago

7 0

I would say that answer B makes more sense that the others. Standard deviation are both described with College and High School. I hope this helps!

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Suppose Paul kicks a soccer ball straight up into the air with an initial velocity of 96 feet per second. The function f(x) = -1

Ludmilka [50]

The zeros are the values of t for which f(t) = 0.
i.e. <span>-16t^2 + 96t = 0
16</span>t^2 - 96t = 16t(t - 6)
16t = 0 or t - 6 = 0
t = 0 or t = 6
Therefore, the zeros are 0, 6

The time taken for the ball to hit the ground is the value of t when f(t) = 0.
i.e. t = 6.

3 0

2 years ago

Please help. I am getting in trouble so please try to be correct...

vichka [17]

Answer: The answer is A 17in2

Step-by-step explanation:

In the question it states that the triangles are congruent (both the same).

first I found the area of the top orange triangle.

the formula to find the area of a triangle is $\frac{1}{2} bh$ (base times Height).

so I did $\frac{1}{2} 3.23* 5.12$ which gave me 8.27.

Since the triangles are congruent (the same) they would both have the same area along with base and height. so I multiplied 8.27 by 2 (because there are two triangles) and got 16.54 which rounds up to 17.

the question also stated to find the APPROXIMATE area (close to the actual, but not completely accurate or exact.)

7 0

1 year ago

Monique made several batches of soup for a potluck supper. Each batch required Three-fourths of a pound of potatoes, and she use

mr Goodwill [35]

Answer:

its 8 2/3

Step-by-step explanation: I got it right on edg

4 0

2 years ago

Read 2 more answers

In 2009, a city with a population of 796,000 had 2,388 births. What is the number of births per 10,000 in the city?

Tom [10]

796,000/2388=10,000/x
796,000x= (2388*10,000)
796,000x/796,000=23,880,000/796,000
x=30 births

7 0

2 years ago

A quality control technician works in a factory that produces computer monitors. Each day, she randomly selects monitors and tes

jeka94

Answer:

There is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 300

p = 5% = 0.05

Alpha, α = 0.05

Number of dead pixels , x = 24

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.05\\H_A: p > 0.05$

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{24}{300} = 0.08$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.08-0.05}{\sqrt{\frac{0.05(1-0.05)}{300}}} = 2.384$

Now, we calculate the p-value from excel.

P-value = 0.00856

Since the p-value is smaller than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

5 0

1 year ago