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Eddi Din [679]
2 years ago
15

Simplify the equation -2(p + 4)2 - 3 + 5p. What is the simplified expression in standard form? ASAP PLEASE!! ILL GIVE EXTRA POIN

TS FOR FIRST ANSWER!!
Mathematics
2 answers:
Katena32 [7]2 years ago
4 0
So you distrubute and get

-2p-8+2-3+5p 
add like terms 
3p-9
ANSWER: 3p-9
Blizzard [7]2 years ago
4 0

Answer:  The required simplified expression in standard form is -2p^2-11p-35.

Step-by-step explanation:  We are given to simplify the following equation and write the simplified expression in standard form :

E=-2(p+4)^2-3+5p~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following formula :

(a+b)^2=a^2+2ab+b^2.

The simplification of expression (i) is as follows :

E\\\\=-2(p+4)^2-3+5p\\\\=-2(p^2+8p+16)-3+5p\\\\=-2p^2-16p-32-3+5p\\\\=-2p^2-11p-35.

Thus, the required simplified expression in standard form is -2p^2-11p-35.

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Tina is playing a computer game. She starts with 100 points, and she loses points based on the following rules: • Each time a pl
Natasha_Volkova [10]

Answer: she must complete 4 levels to have a point fewer than 20

Step-by-step explanation:

Given the following :

Starting point = 100 points

Passing a level = - 8 points

Catching a flower = - 3 points

Suppose Tina catches 6 flowers per level

Number of levels she must complete to have fewer Than 20 points

Total number of points lost per level:

Catching 6 flowers = -(6 × 3)

Passing the level = - 8

= - 18 + - 8 = - 26 points

Number of levels she must complete to have < 20

Let number of levels = y

Starting points - (26 × number of levels) < 20

100 - (26y) < 20

100 - 26y < 20

-26y < 20 - 100

-26y < - 80

y > 80/26

y > 3.07

Hence she must complete 4 levels to have a point fewer than 20

8 0
2 years ago
Read 2 more answers
Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.
Evgesh-ka [11]

A="b is in the middle"

B="c is to the right of b"

C="The letter def occur together in that order"

a) b can be in 7 places, but only one is the middle. So, P(A)=1/7

b) X=i, "b is in the i-th position"

Y=j, "c is in the j-th position"

P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}

P(B)=1/2

c) X=i, "d is in the i-th position"

Y=j, "e is in the j-th position"

Z=k, "f is in the i-th position"

P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

A and C aren't independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

B and C aren't independent

8 0
1 year ago
A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is
anzhelika [568]
You need to solve for one variable in equation 1 and substitute it in equation 2 to solve.

Equation 1: x+y=24
x= number of 3 pt questions
y= number of 5 pt questions
24= Total number of questions

Equation 2: 3x+5y=100
100= Total point value possible on test
3x= point value of 3 pt questions
5y= point value of 5 pt questions

x+y=24
Subtract y from both sides
x=24-y

Substitute in equation 2:
3x+5y=100
3(24-y) +5y=100
72-3y+5y=100
72+2y=100
Subtract 72 from both sides
2y=28
Divide both sides by 2
y=14

Substitute y=14 back in to solve for x:
3x+5y=100
3x+5(14)=100
3x+70=100
Subtract 70 from both sides
3x=30
Divide both sides by 3
x=10

So there are 10 three point questions
There are 14 five point questions.

Hope this helped! :)
6 0
1 year ago
Read 2 more answers
2. The seniors at our high school decided to play a prank on the principal by completely filling his office with
melisa1 [442]

Answer:

idk

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Find the difference: square root of 20 - square root of 80
Mamont248 [21]

Answer:

-2\sqrt{5}

Step-by-step explanation:

\sqrt{20} = \sqrt{10*2} = \sqrt{5 * 2 *2} = \sqrt{2^2 * 5} = 2\sqrt{5}   \\\\\sqrt{80} = \sqrt{20*4} = \sqrt{5*4 *4} = \sqrt{4^2 * 5} = 4\sqrt{5}   \\\\2\sqrt{5} - 4\sqrt{5} = -2\sqrt{5}

8 0
1 year ago
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