How many ways can we pick three distinct integers from {1, 2, ..., 15} such that their sum is divisible by 3?

Mathematics

1 answer:

gogolik [260]2 years ago

5 0

Answer:

Clearly from 1 to 15 we can only have the sum 6,9,12 and 15 to be divisible by 3.

Now meaning we have 4! ( 4 factorial) which implies 4x3x2x1= 24 .

We have 24 ways to pick distinct integers that are divisible by 3.

Step-by-step explanation:

The first thing you need to do is to look for numbers that are divisible by 3. Then you take its factorial

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<h3>Solution:</h3>

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