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____ [38]
2 years ago
5

Suppose that the terminal point determined by t is the point 12 13 , 5 13 on the unit circle. Find the terminal point determined

by each of the following. (a) π − t (x, y) = (b) −t (x, y) = (c) π + t (x, y) = (d) 2π + t (x, y)
Mathematics
1 answer:
Tom [10]2 years ago
5 0

Answer:

  (a)  (-12/13, 5/13)

  (b)  (12/13, -5/13)

  (c)  (-12/13, -5/13)

  (d)  (12/13, 5/13)

Step-by-step explanation:

(a) The terminal point is effectively reflected across the y-axis, so the sign of the x-coordinate changes. (-12/13, 5/13)

__

(b) The terminal point is effectively reflected across the x-axis, so the sign of the y-coordinate changes. (12/13, -5/13)

__

(c) The terminal point is effectively reflected across the origin, so the signs of both coordinates change. (-12/13, -5/13)

__

(d) The terminal point is mapped to itself, so its coordinates remain unchanged. (12/13, 5/13)

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The amount of garbage, G, in tons per week, produced by a city with population p, measured in thousands of people, is given by G
ExtremeBDS [4]

Answer:

12 = f(40)

Step-by-step explanation:

From the given information:

We are being told that:

G = tons per week

p = people in thousands

However, the relation existing between the amount of garbage that is produced by a city with population p can be expressed as:

G = f(p)

Similarly, they said there exists a total population of 40000 persons in the town of Tola. i.e. 40 thousand and also 12 tons of garbage is produced by week i.e. that will be the value for G.

Then, we have:

12 = f(40)

4 0
2 years ago
Harper knows he is 50 yards from school. The map on his phone shows that the school is 34 inch from his current location. How fa
laila [671]

To solve this problem you must apply the proccedure shown below:

1. We know that 1 yard is 36 inches, therefore, 50 yards expressed in inches is:

(50)(36)=1800in

2. If he is 50 yards from school and the map shows that the school is 34 inches from his current location, when it shows 3 inches the real distance is:

\frac{(1800in)(3in)}{34in}=158.82in

3. If you can to express it in yards:

\frac{158.82}{36} =4.41 yd

Therefore, the answer is: 158.82 inches or 4.41 yards.

8 0
2 years ago
Read 2 more answers
Including Jose, there are eight people in his family.
SIZIF [17.4K]

Answer:

840

Step-by-step explanation:

Since the order matters, we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

The first seat is Jose's.

The remaining four are organized among the other 7 members. So

P_{(7,4)} = \frac{7!}{(7-4)!} = 840

So the correct answer is:

840

7 0
2 years ago
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Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability
Anna11 [10]

Answer:

  • a. 0.1647;
  • b. 0.7153;
  • c. 0.4453.

Step-by-step explanation:

By definition, if two event A and B are independent, then

P(A\cap B) = P(A) \cdot P(B). (P(A\cap B) is the probability that the outcome of both event A and event B are true.)

<h3>a.</h3>

Since the outcome of these two events are independent,

\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}.

<h3>b.</h3>

The logic not operator \lnot or the prime superscript ^{\prime} denotes that an event does not happen.  

P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39.

P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73.

Since the two events \texttt{Jane} and \texttt{Joe}, \texttt{Jane}^{\prime} and \texttt{Joe}^{\prime} are also independent. Probability that neither professor got funded:

P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847.

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153.

<h3>c.</h3>

Similarly, since the two events \texttt{Jane} and \texttt{Joe}, \texttt{Jane} and \texttt{Joe}^{\prime} are also independent. Probability that Jane but not Joe got funded:

P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453.

4 0
2 years ago
Evaluate the integral. 17 sin2(x) cos3(x) dx step 1 since 17 sin2(x) cos3(x) dx has an odd power of of cos(x), we will convert a
lord [1]
To evaluate 17 int (sin^2 (x)  cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x) 
Cos^3(x) = cosx * (1 - sin^2 (x)) = cosx - cosxsin^2x
So we have 17 int (sin^2x(cosx - cosxsin^2x))
int (sin^2x(cosx)dx - int (sin^4xcosx)dx. ----------(1)
Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have 
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]
7 0
1 year ago
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