Answer:
Option B.
Step-by-step explanation:
It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.
RT is altitude on side SQ, ST=9, TQ=16 and SR=x.
In ΔSRQ and ΔSTR,
(Reflexive property)
(Right angle)
By AA property of similarity,
Corresponding parts of similar triangles are proportional.
Substitute the given values.
On cross multiplication we get
Taking square root on both sides.
The value of x is 15. Therefore, the correct option is B.
Answer:
Step-by-step explanation:
Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.
m∠2 = 50°
m∠1 + m∠2 = 180° [Linear pair of angles]
m∠1 = 180° - 50°
m∠1 = 130°
m∠3 = m∠1 = 130° [Vertically opposite angles]
m∠3 + m∠5 = 180° [Consecutive interior angles]
m∠5 = 180° - m∠3
= 180° - 130°
= 50°
m∠6 + m∠5 = 180° [Linear pair of angles]
m∠6 = 180° - 50° = 130°
The answer would be
You got it right
I wish i saw this when i needed jt too
Explanation
Absolutely
Fifty Nine And Thirty Plus Twenty Nine
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
